Is (4 × root 2) square = 16 times root 4

Is (4 × root 2) square = 16 times root 4

(4 × root 2) square
=16 times root 4
=16×2
=32

What is a (x1, Y2, Z3) B (X2, Y2, Z2) vector AB

AB is (x2-x1,0, z2-z3)

Given | Z1 | = | Z2 | = | Z3 | = 1, find the value of | (1 / Z1 + 1 / Z2 + 1 / Z3) / Z1 + Z2 + Z3 |

|Z1 | & sup2; = Z1 × (the conjugate complex number of z1), for the convenience of using Z1 'to express the conjugate complex number of Z1, then 1 / Z1 = Z1'

The unit vector collinear with vector a = (- 5, 12) is______ ．

Because a = (- 5, 12) = 13 (− 5131213) or a = (- 5, 12) = − 13 (513, − 1213), the unit vector collinear with vector a = (- 5, 12) is 13 (− 5131213) or − 13 (513, − 1213). So the answer is 13 (− 5131213) or − 13 (513, − 1213)

As shown in the figure, ad is the height of △ ABC, be bisects ∠ ABC and intersects ad with E. if ∠ C = 70 ° and ∠ bed = 64 °, calculate the degree of ∠ BAC

∵ ad is the height of △ ABC, ∵ C = 70 °, ∵ DAC = 20 °, ∵ be bisection ∵ ABC intersects ad with E, ∵ Abe = ∵ EBD, ∵ bed = 64 °, ∵ Abe + ∵ BAE = 64 °,