How to solve the system of equations composed of one variable quadratic equation and two variable quadratic equation 3x+y-6=0 ① x^2+y^2-2y-4=0 ② How did it work out, My answer here is to get rid of Y x^2-3x+2=0 In my opinion, the answers are direct ① and ② The Y in is deleted, and then ② - ① comes out I hope you can calculate it for me and explain how to calculate it. Please be more detailed,
3x + y-6 = 0, y = - 3x + 6 is substituted into ② 10x ^ 2-30x + 20 = 0 to get x ^ 2-3x + 2 = 0
X = 1 or x = 2
When x = 1, y = 3
When x = 2, y = 0
On binary quadratic equations or systems of equations
(1) Finding the positive integer solution of equation 7x + 4Y = 80
(2) If LA + B + 6I + (3a + 2B + 15) ^ 2 = 0, find the value of (a-b) ^ 2
(3) If the equations {x + y = 3 and {(m-n) x = 8-y about X and Y
mx+5y=my x-y=-1
The solution of 1 / 14m-1 / 8N is the same
(1)7x+4y=80
x=4 y=13
x=8 y=6
(2)la+b+6I+(3a+2b+15)^2=0
a+b+6=0
3a+3b+18=0
3a+2b+15=0
a=-3 b=-3
(a-b)^2=0
(3) x+y=3
x-y=-1
x=1 y=2
m-n=6
m+10=2m
m=10 n=4
1/14m-1/8n=5/7-1/2=3/14
Known: x2 + y2-10x-2y + 26 = 0, find the value of X, y
X 2 + y 2-10x-2y + 26 = 0, x 2 + y 2-10x-2y + 25 + 1 = 0, (X-5) 2 + (Y-1) 2 = 0, X-5 = 0 or Y-1 = 0, the solution is x = 5, y = 1
Given Tan α = 1 / 3, Tan β = - 2, find the value of Tan (α - β)
tan(α-β)
The original formula = (Tan α - Tan β) / (1 + Tan α, Tan β)
=(1/3+2)/[1+1/3*(-2)]
=(7/3)/(1/3)
=7
Is that ok?
The line L passing through the left focus F of the ellipse x ^ 2 / 9 + y ^ 2 = 1 intersects the ellipse at PQ. If the distance between P and Q is equal to the length of the minor axis, calculate the inclination angle of the line l?
RT, I don't know if I understand it wrong or what, I just can't figure it out. I hope the gods can give me some advice!
Let the slope of the line be K, and the equation be y = K (x + 2 √ 2), substitute x ^ 2 / 9 + y ^ 2 = 1 and eliminate y to get: (1 + 9K & sup2;) x & sup2; + 36 √ 2K & sup2; X + 9 (8K & sup2; - 1) = 0, and the discriminant △ is 36 & sup2; × 2K ^ 4-36 (1 + 9K & sup2;) (8K & sup2; - 1) = 36 [72 K ^ 4 - (72 K ^ 4
How many minutes and degrees is 450 seconds
450÷60=70………… thirty
450 seconds = 70 minutes 30 seconds = 1 degree 10 minutes 30 seconds
What is the linear equation parallel to the line 2x + 3Y + 5 = 0 and the sum of intercept on two coordinate axes is 10 / 3?
Let + C = 0
Because: the line is parallel to the line 2x + 3Y + 5 = 0
So: a = 2, B = 3
So: it's time
So: when x = 0, y = - C / 3
When y = 0, x = - C / 3
Because: - C / 3 + (- C / 2) = 10 / 3
So: C = - 4
Therefore, the linear equation is 2x + 3y-4 = 0
Remember to offer a reward next time!
39-1,38+2,37-3,36+1,35-2,34+3,...
Quantitative relationship
The first number is decreasing, the second number is 123 cycle, and the symbol in the middle is - + cycle
Given a point a (4,3) on an image with a linear function y = 2x-n, if the intersection of the image and the Y axis is B, then the area of the triangle AOB is
So point B (0, - 5), after drawing, so s = 0.5 * 4 * 5 = 10
Let the sum of the first n terms of the sequence {an} be Sn, and the points (n, SNN) (n ∈ n +) are all on the image of the function y = 3x-2. Then the general formula of the sequence {an} is______ .
Because (n, SNN) is on the image of y = 3x-2, we substitute (n, SNN) into the function y = 3x-2 to get: SNN = 3N − 2, that is {s}_ {n} Then an = sn-sn-1 = n (3n-2) - (n-1) [3 (n-1) - 2] = 6n-5. When n = 1, S1 = 1, so the answer is: an = 6n-5 (n ∈ n +)