How to solve the system of equations composed of one variable quadratic equation and two variable quadratic equation 3x+y-6=0 ① x^2+y^2-2y-4=0 ② How did it work out, My answer here is to get rid of Y x^2-3x+2=0 In my opinion, the answers are direct ① and ② The Y in is deleted, and then ② - ① comes out I hope you can calculate it for me and explain how to calculate it. Please be more detailed,

How to solve the system of equations composed of one variable quadratic equation and two variable quadratic equation 3x+y-6=0 ① x^2+y^2-2y-4=0 ② How did it work out, My answer here is to get rid of Y x^2-3x+2=0 In my opinion, the answers are direct ① and ② The Y in is deleted, and then ② - ① comes out I hope you can calculate it for me and explain how to calculate it. Please be more detailed,

3x + y-6 = 0, y = - 3x + 6 is substituted into ② 10x ^ 2-30x + 20 = 0 to get x ^ 2-3x + 2 = 0
X = 1 or x = 2
When x = 1, y = 3
When x = 2, y = 0

On binary quadratic equations or systems of equations
(1) Finding the positive integer solution of equation 7x + 4Y = 80
(2) If LA + B + 6I + (3a + 2B + 15) ^ 2 = 0, find the value of (a-b) ^ 2
(3) If the equations {x + y = 3 and {(m-n) x = 8-y about X and Y
mx+5y=my x-y=-1
The solution of 1 / 14m-1 / 8N is the same

(1)7x+4y=80
x=4 y=13
x=8 y=6
(2)la+b+6I+(3a+2b+15)^2=0
a+b+6=0
3a+3b+18=0
3a+2b+15=0
a=-3 b=-3
(a-b)^2=0
(3) x+y=3
x-y=-1
x=1 y=2
m-n=6
m+10=2m
m=10 n=4
1/14m-1/8n=5/7-1/2=3/14

Known: x2 + y2-10x-2y + 26 = 0, find the value of X, y

X 2 + y 2-10x-2y + 26 = 0, x 2 + y 2-10x-2y + 25 + 1 = 0, (X-5) 2 + (Y-1) 2 = 0, X-5 = 0 or Y-1 = 0, the solution is x = 5, y = 1

Given Tan α = 1 / 3, Tan β = - 2, find the value of Tan (α - β)

tan（α-β）
The original formula = (Tan α - Tan β) / (1 + Tan α, Tan β)
=(1/3+2)/[1+1/3*(-2)]
=(7/3)/(1/3)
=7
Is that ok?

The line L passing through the left focus F of the ellipse x ^ 2 / 9 + y ^ 2 = 1 intersects the ellipse at PQ. If the distance between P and Q is equal to the length of the minor axis, calculate the inclination angle of the line l?
RT, I don't know if I understand it wrong or what, I just can't figure it out. I hope the gods can give me some advice!

Let the slope of the line be K, and the equation be y = K (x + 2 √ 2), substitute x ^ 2 / 9 + y ^ 2 = 1 and eliminate y to get: (1 + 9K & sup2;) x & sup2; + 36 √ 2K & sup2; X + 9 (8K & sup2; - 1) = 0, and the discriminant △ is 36 & sup2; × 2K ^ 4-36 (1 + 9K & sup2;) (8K & sup2; - 1) = 36 [72 K ^ 4 - (72 K ^ 4

How many minutes and degrees is 450 seconds

450÷60=70………… thirty
450 seconds = 70 minutes 30 seconds = 1 degree 10 minutes 30 seconds

What is the linear equation parallel to the line 2x + 3Y + 5 = 0 and the sum of intercept on two coordinate axes is 10 / 3?

Let + C = 0
Because: the line is parallel to the line 2x + 3Y + 5 = 0
So: a = 2, B = 3
So: it's time
So: when x = 0, y = - C / 3
When y = 0, x = - C / 3
Because: - C / 3 + (- C / 2) = 10 / 3
So: C = - 4
Therefore, the linear equation is 2x + 3y-4 = 0
Remember to offer a reward next time!

39-1,38+2,37-3,36+1,35-2,34+3,...
Quantitative relationship

The first number is decreasing, the second number is 123 cycle, and the symbol in the middle is - + cycle

Given a point a (4,3) on an image with a linear function y = 2x-n, if the intersection of the image and the Y axis is B, then the area of the triangle AOB is

So point B (0, - 5), after drawing, so s = 0.5 * 4 * 5 = 10

Let the sum of the first n terms of the sequence {an} be Sn, and the points (n, SNN) (n ∈ n +) are all on the image of the function y = 3x-2. Then the general formula of the sequence {an} is______ ．

Because (n, SNN) is on the image of y = 3x-2, we substitute (n, SNN) into the function y = 3x-2 to get: SNN = 3N − 2, that is {s}_ {n} Then an = sn-sn-1 = n (3n-2) - (n-1) [3 (n-1) - 2] = 6n-5. When n = 1, S1 = 1, so the answer is: an = 6n-5 (n ∈ n +)