既知のi1=14.1sin(628t-50°)A,i2=70.7sin(628t+40°)A,i=i1+i2,求i最大,rms,

既知のi1=14.1sin(628t-50°)A,i2=70.7sin(628t+40°)A,i=i1+i2,求i最大,rms,

i1=10*(2)^(1/2)sin(628t-50°)A,i2=50*(2)^(sin(628t+40°),これら2つのベクトル差は正確に90度であるため、iの最大値は(200+5000)^(1/2)=72.11A,実効値は72.11/(2)^(1/2)=50.998A