Let z = y ^ 2E ^ x find the partial derivatives DZ / DX and D ^ 2Z / dy ^ 2

Let z = y ^ 2E ^ x find the partial derivatives DZ / DX and D ^ 2Z / dy ^ 2




Dy / DX = KY, y = yo when x = 0. Solving differential equation y (x). Steps, thank you


1 / YDY = kdx, LNY = KX + C, y (x) = KX power of E + C power of E, when x = 0, y (0) = yo = C power of E, so y (x) = KX power of E + yo



Using arithmetic to solve math problems
The distance between a and B is 475km. The freight car drives from a to B at the speed of 35km / h. five hours later, the passenger car drives from B to a, and after four hours, the two cars meet. How many km / h does the passenger car travel?


{475-35*(5+4)}/4
=(475-35*9)/4
=(475-315)/4
=160/4
=40



The area formula of a rectangle is expressed by letters (). If a = 4 meters and B = 3.5 meters, the area of a rectangle is () square meters
The two integers adjacent to a are () and (their sum is)(


The area formula of a rectangle is expressed by letters (s = AB). If a = 4 meters and B = 3.5 meters, the area of a rectangle is (14) square meters



The definition field of function y = lgx + 1 is?


X is greater than 0



The diameter of a cylindrical steel is 20cm when it is cut for 1m. The volume of the cut steel accounts for 1 / 12 of the steel. What is the volume?
2. Put some potatoes on the bottom with a radius of 10cm for cleaning. This is the water depth of 30cm in the container. When you take out the potatoes, the water level drops by 3cm. What is the volume of potatoes?


(0.1 square π × 1) △ 1 / 12 = 0.12 π
100π×30-100π×27=300π



Help solve 2 geometry problems
1 in ⊙ o with a radius of 2cm, there is a chord AB with a length of 2 times the root 3, then the degree of the center angle of the circle opposite to the chord AB is ()
If a chord divides a semicircle into three equal arcs, the ratio of the chord length to the radius length is ()


120,1



If the square of a + the square of B + AB = 3AB, then 2A / b =?


That is a & sup2; + B & sup2; - 2Ab = 0
(a-b)²=0
a-b=0
b=a
So 2A / b = 2A / a = 2



Using derivative to find the square derivative of the definition function f (x) = x,


△y=(x+h)^2-x^2=2hx+h^2
f'(x)=(h→0)lim(△y/h)=lim(2x+h)=2x



1. Make an equilateral triangle Abe with the edge ab of the square ABCD as the edge. When the point E is inside the square, ∠ Dec=
When point E is outside the square, ∠ Dec=
2. In diamond ABCD, AE ⊥ BC is equal to e, AF ⊥ CD and F, if be = EC, then ∠ EAF=
3. Make a diagonal BD through each vertex of the quadrilateral ABCD, and the parallel lines of AC form a quadrilateral efgh. If the quadrilateral efgh is a diamond, then the original quadrilateral is a diamond
A diamond B parallelogram C rectangle D quadrilateral with equal diagonal


1. When the e-point is inside the square, ∫ DAE = 30 ° ad = AE, ∫ AED = 1 / 2 (180 ° - 30 °) = 75 ° similarly, ∫ BEC = BCE = 75 ° and ∫ EDC = ECD = 15 ° Dec = 180 ° - 2 × 15 ° = 150 ° when the e-point is outside the square, ∫ DAE = 90 ° + 60 ° = 150 ° a