When x takes what value, the value of formula 3x + 1 is smaller than that of formula 5x-5 / 2?

When x takes what value, the value of formula 3x + 1 is smaller than that of formula 5x-5 / 2?

The value of formula 3x + 1 is smaller than that of formula 5x-5 / 2
Then 3x + 12 / 2 + 5 / 2
2x>7/2
x>7/4
So when x > 7 / 4, the value of formula 3x + 1 is smaller than that of formula 5x-5 / 2

When x = what, the values of molecule 2 of formula X-1 and molecule 2 of formula 3x + 4 are opposite to each other
When x=_____ If the solution of equation (X-2) / 2 - (x-a) / 3 = 1 is x = 1, then a = 3. If the solution of equation 2x-5 = 1 is the same as that of equation 1 - (3a-x) / 3 = 0, then a = when m is the value, the value of equation (M-8) / 3 and & frac14; m + 5 are equal

（1） x=-3/5 （2）a=1 （3）a=-11/6 （4）m=92

Lao she visited the grassland of Inner Mongolia

Lao she visited the grassland of Inner Mongolia

Let x0 be the root of the equation INX + x = 4, and x0 ∈ (k, K + 1), find the positive integer K

y=lnx+x-4
Obviously, y is a monotone increasing function, so the equation has only one solution at most
And Y (1) = - 3

Simple calculation: (+ 1) + (- 2) +... + (+ 99) + (- 100)

Put forward the positive and negative terms respectively, 1 + 3 + 5 is added to 99, equal to (1 + 99) times 50 divided by 2, equal to 2500, from 2 + 4 + 6 to 100, equal to (2 + 100) times 50 divided by 2, two minus - 50
The second method, which is simpler, takes two adjacent numbers as a whole, and the sum is equal to - 1. There are 50 groups in total, so it is equal to - 50

Question 1: Verification: if the middle line of an edge of a triangle is equal to half of the edge, then the triangle is a right triangle. (hint: make a circle with the diameter of the edge) question 2: Verification: a parallelogram inscribed in a circle is a rectangle

A
E E
D
BC
As shown in the figure, extend ad to e so that ED = ad
Connecting AE, CE
Because BD = de BD = AC
So AC = be and AC and be are equally divided
The quadrilateral abce is a rectangle, so the triangle ABC is a rectangle

The price of a commodity is reduced by 1 / 10 and then increased by 1 / 10, compared with the original price

The current price is (1-1 / 10) x (1 + 1 / 10) = 0.9x1.1 = 0.99
Less than before

Given that the domain of function f (x) is [- 1,2], then the domain of function y = f (x + 1) + F (x2-1) is---

When there is no special restriction, domain refers to the scope of X that makes the expression meaningful
The definition field of F (x) is [- 1,2], indicating that the quantity in brackets after f must be [- 1,2], so - 1 ≤ x + 1 ≤ 2 and - 1 ≤ x ^ 2-1 ≤ 2
The root of solution 3 ≤ x ≤ 1

x²+[(√5-1)/(2)×x]²=(5-√5)²
I see the answer is X & sup2; = 10-2 √ 5

The original formula is rewritten as: X & sup2; + [(√ 5 - 1) / (2)] & sup2; × X & sup2; = (5 - √ 5) & sup2;
That is: (1 + (√ 5 - 1) & sup2; / 4) × X & sup2; = (5 - √ 5) & sup2;
x = ± ( 5 - √5 )² / ( 1 + (√5 - 1)² / 4 )
= ±(2√((5 (3 - √5))/(5 - √5)))

A kind of TV set, the original price is 1200 yuan, now the price is 1080 yuan?

(1200-1080) △ 1200, = 120 △ 1200, = 10%; answer: reduce the price by 10%