If the expansion of (X & # 178; + MX + 8) (X & # 178; &; \ 3x + n) does not contain X &; and X &; terms, find the value of M and n

If the expansion of (X & # 178; + MX + 8) (X & # 178; &; \ 3x + n) does not contain X &; and X &; terms, find the value of M and n


(x²+mx+8)(x²+3x+n)=x^4+(m+3)x^3+(3m+n+8)x²+(mn+24)x+8n
The expansion does not contain X & # 178; and X & # 179; terms, M + 3 = 0, 3M + N + 8 = 0
So m = - 3, n = 1
If (X & # 178; + MX + 8) (X & # 178; - 3x + n) = x ^ 4 + (M-3) x ^ 3 + (- 3M + N + 8) x & # 178; + (mn-24) x + 8N
The expansion does not contain x &# 178; and X &# 179; terms, M-3 = 0, - 3M + N + 8 = 0
M = 3, n = 1



Given that the maximum value of the function y = ax (a > 0 and a ≠ 1) on [1,2] is greater than the minimum value A2, then the value of a is ()
A. 12 or 32B. 32c. 12D. 2 or 3


When a > 1, the function y = ax (a > 0 and a ≠ 1) is an increasing function on [1,2], a2-a = A2 can be obtained from the meaning of the problem, and the solution is a = 32. When 0 < a < 1, the function y = ax (a > 0 and a ≠ 1) is a decreasing function on [1,2], and A-A2 = A2 can be obtained from the meaning of the problem, and the solution is a = 12



Given the exponential function y = (2a2-5a + 3) ax power, find the maximum and minimum of F (x) on [0, a]


Because of the sign of coefficient and the relationship between the base of a ^ X and 1, this problem needs to be discussed by classification
Because f (x) is the maximum value on [0, a], the base number a > 0
When a = 1, y = 0, the maximum and minimum are 0;
When 01, a ^ x increases monotonically, 1 ≤ x ≤ a ^ A, then the sign of 2A ^ 2-5A + 3 is uncertain
If 1



If the difference between the maximum value and the minimum value of the exponential function y = ax on [- 1, 1] is 1, then the base a is equal to ()
A. 1+52B. −1+52C. 1±52D. 5±12


When a > 1, the function y = ax is an increasing function in the domain [- 1,1], a-a-1 = 1, a = 1 + 52. When 1 > a > 0, the function y = ax is a decreasing function in the domain [- 1,1], a-1-a = 1, a = − 1 + 52, so D



Can a number of modify uncountable nouns? Why?


A number of can't modify uncountable nouns
It modifies countable nouns
You can count the number if you want
So a number of modifies countable nouns
You can use a huge amount of / an amount of to modify uncountable nouns~
The number of is The quantity of is quite different from its meaning



"The visual image of a horizontal plane figure is a plane figure", right?


If it is a plane figure drawn, the intuitive figure must be a plane figure;
If it is a three-dimensional plane figure, the intuitive figure is a three-dimensional figure



Please write an English essay about your family's three meals a day, no less than 50 words


i have a good family,we live happily everyday,now,i will tell you about my daily died.in the morning,we eat some bread,milk,and eggs.at the noon,we eat fish ,meat,rise,it"s very delicious.in the evening,we have some meat and vegetables for supper,it"s my and my parents" daily diet,what about yours?



It is known that: as shown in the figure, point C is on line AB, and point Mn is the midpoint of AC and BC respectively. (1) if line AC = 10, BC = 6, find the length of Mn. (2) according to the calculation process and results of (1), let AC + BC = a, and other conditions remain unchanged. Can you guess the length of Mn? Please use a simple expression to express the rule you find. (3) if point C is on line AB, ab = a, and other conditions remain unchanged, can you think of the length of Mn?


(1)∵MC=1/2AC,NC=1/2BC
∴MC+NC=1/2(AC+BC)
∴MN=1/2(10+6)=8
(2)MN=1/2 a
(3) Classified discussion
If point C is to the left of point a, Mn = 1 / 2bc-1 / 2Ac
If point C is on line AB, then Mn = 1 / 2Ab = 1 / 2A
If point C is to the right of point B, Mn = 1 / 2ac-1 / 2BC



Ask two English phrases
Does signal in have this form
What else can break up follow?


Signal in is not a fixed collocation, but signal in is a fixed collocation



Xiao Ming adds 2 to the numerator of a fraction and subtracts 2 from the denominator. The difference between the numerator and denominator of the new fraction is 6, which is about 5 out of 7. Do you know what the original fraction is?


Let the original fraction A / B, the new one be (a + 2) / (b-2) = 5 / 7, which is in duplicate, and B-2 - (A-2) = 6, which is in two forms. The original fraction is 13 / 23