How to solve the equation that 6x times 3 / 7 equals 9 / 10?

How to solve the equation that 6x times 3 / 7 equals 9 / 10?

6X multiplied by 3 / 7 is 9 / 10
6x=9/10/(3/7)
6x=21/10
x=7/20

Solve the equation. 4x + 20 = 561.8 + 7x = 3.95x-8.3 = 10.7

（1）4x+20=56     4x+20-20=56-20           4x=36，        4x÷4=36÷4，    ...

How to solve 4x + 8-x = 56

4x+8-x=56
3x=56-8
3x=48
x=16

Given that the line L1: y = 2x + 3, the line L2 and L1 are symmetric with respect to the line y = - x, then the slope of L2 is ()
The symmetric line of L1 with respect to the line y = - x is - x = - 2Y + 3,

Line L1: y = 2x + 3
Slope K1 = 2
The slope of the line y = - x is k = - 1
Let L2 slope be K2
From the formula Tan θ = (K2 - K1) / (1 + k1k2)
(k-k1)/(1+kk1)=(k2-k)/(1+kk2)
(-1-2)/(1-2)=(k2+1)/(1-k2)
3/2=(k2+1)/(1-k2)
3(1-k2)=(k2+1)
3-3k2=k2+2
4k2=1
The solution is K2 = 1 / 4
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Don't feed the monkeys --- the dirty food

Don't feed monkeys with dirty food
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If one vertex of an equilateral triangle is at the coordinate origin and the other two vertices are on the parabola y2 = 2x, then the side length of the equilateral triangle is___ ．

Let the side length be a, then the other two points are (32, A2), (32, - A2), and the parabolic equation is a = 43, so the answer is 43

How many natural numbers divide 732 and the remainder is 12?

The remainder of division 732 is 12, which means that division (732-12) = 720 is divisible
So there are the following natural numbers: 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 16, 18, 20, 24, 30, 36, 40, 45, 48, 60, 72, 80, 90, 120, 144, 180, 240, 360, 720
30 in total

Is the polar equation P = cos (PI / 4-x) transformed into a rectangular equation?

ρ＝√2/2（cosx＋sinx）
ρ*ρ=√2/2ρcosx+√2/2ρsinx
x^2+y^2=√2/2 x+√2/2 y.

On the practice of "integral multiplication and division and factorization" in grade two of junior high school
Given a + 1 / a = 3, then the value of a & sup2; + 1 / A & sup2; is__________

a²+1/a²=(a+1/a)^2-2*[a*(1/a)]
=3^2-2
=9-2
=7

If the vertex of the quadratic function y = ax ^ 2 + BX = C is in the first quadrant and passes through the point (0,1), (- 1, O), then is the variation range of S = a + B + C

The range of S is the range of F (1)
Because the vertex is in the first quadrant and passes (0,1), (- 1,0), a is less than 0
First, if the vertex is infinitely close to the y-axis, f (1) is infinitely close to 0 (the function is symmetric about the y-axis)
When the abscissa of the vertex tends to infinity, the segment from - 1 to 1 can be regarded as a line segment, and then f (1) is infinitely connected to 2
To sum up, 0