Suppose x = 3, y = 6, z = 5, what is the value of the expression (x ^ 2 + y) / Z What is the solution

Suppose x = 3, y = 6, z = 5, what is the value of the expression (x ^ 2 + y) / Z What is the solution

three

What is the value of expression 6 * 7 / 8mod9?

5

Calculation method of fourth order determinant
a 1 1 1
1 a 1 1
1 1 a 1
1 1 1 a

Add 2,3,4 columns to the first column a + 3 1 1A + 3 a 1 1A + 3 1 a 1A + 3 1 a 2,3,4 rows subtract the first row a + 3 1 1 10 A-1 000 A-1 000 A-1 determinant = (a + 3) (A-1) ^ 3. Please accept^_^

A simple algorithm of 104 times 31 and 4200 divided by 84

104×31
=(100+4)×31
=100×31+4×31
=3100+124
=3224
4200÷84
＝4200÷42÷2
＝100÷2
＝50

Who can help me find the limit of (x / SiNx) when x approaches zero,

When x ~ 0,
sinx～x,
So when x ~ 0,
x/sinx=x/x=1

Oral calculation: 1 / 6 by 49 by 1 / 7, 2.4 by 3 / 8, 3 / 4 by 40% + 0.75 by 3 / 5, and below
Simple calculation: 23 times (5 / 23-5 / 32) times 32
[1 / 2 + (3 / 4 + 4 / 5)] divided by 7 / 10

1 / 6 times 49 times 1 / 7 = 7 / 6
2.4 times 3 / 8 = 6.4,
Simple calculation
3 / 4 times 40% + 0.75 times 3 / 5
=0.3+1.25
=1.55
23 times (5 / 23-5 / 32) times 32
=23 by 5 of 23 by 32-23 by 5 of 32 by 32
=160-115
=45
[1 / 2 + (3 / 4 + 4 / 5)] divided by 7 / 10
=(1 / 2 + 31 / 20) divided by 7 / 10
=41 out of 20 divided by 7 out of 10
=41 out of 14

((A & sup2;) & sup2; - (B & sup2;) & sup2;) - (A & sup2; C & sup2; - B & sup2; C & sup2;) = 0 factorization

((a²)²-(b²)²)-(a²c²-b²c²)=(a²-b²)(a²+b²)- c²(a²-b²)=(a²-b²)(a²+b²- c²)=(a-b)(a+b)(a²+b²- c...

Skillfully calculate 12.5 * (36-7 1 / 5) divided by 3.6

12.5 * (36-7 and 1 / 5) divided by 3.6
=12.5*36÷3.6-12.5*7.2÷3.6
=12.5*10-12.5*2
=125-25
=100

Given that the straight line L passes through the point P (1,1) and the inclination angle α = π / 6, the parameter equation of the straight line L is written, and the detailed points of the process are given,

∵ the straight line passes through the point P (1,1), and the inclination angle is π / 6,
The linear equation is Y-1 = Tan (π / 6) (x-1)
(y-1)/sin(π/6) =(x-1)/cosπ/6
Let t = (Y-1) / sin (π / 6) = (x-1) / cos π / 6
Then x = 1 + T × cos π / 6, y = 1 + T × sin (π / 6)
The parameter equation is x = 1 + (√ 3T) / 2, y = 1 + T / 2, (t is the parameter)

Given that 5x + 0.8 = 19.3, then 2x-1.4=______ ．

The & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp & nbsp; & nbsp; & nbsp; & nbsp; & amp & nbsp; & nbsp; & nbsp & nbsp; & nbsp; & nbsp & nbsp; & amp & nbsp; & nbsp; & amp & nbsp; & nbsp & nbsp; & nbsp; & nbsp & nbsp & nbsp & nbsp; & nbsp & nbsp; & nbsp; & amp & nbsp; & nbsp; & amp & nbsp; & nbsp; & nbsp; & nbsp & nbsp; & nbsp; & & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & amp & nbsp; & nbsp; & nbsp; & & nbsp; & & nbsp; & nbsp; & nbsp; X = 3.7; substitute x value into 2x-1.4 to get 2 × 3.7-1.4 = 6