Why can high voltage transmission reduce power loss

Why can high voltage transmission reduce power loss

The output power of the generator P is constant, P = UI. If high voltage transmission is adopted, the current I in the transmission circuit is small. According to Joule's law, q = I square RT, the heat generated by the transmission line is less, and the electric energy loss is less. I hope you can understand,

If the electrostatic force does positive work on a negative charge, then is the expression of the work negative or positive?
Confused! Hurry!

Positive function plus sign

It is known that the wiring of three-phase three wire active energy meter is wrong, and its wiring mode is A-phase element UCA.IA , c-phase element UBA.IC Please write out the expressions of two component power PA, PC and total power P, and calculate the correction factor K (three-phase load balance) to draw a vector diagram

Let Φ be the vector angle of phase voltage and phase current, then the expression of active power of three-phase three wire watt hour meter is: P = uabiacos Φ ABA + ucbiccos Φ CBC (Φ ABA is the vector angle of UAB and IA, and Φ CBC is the vector angle of UCB and IC), which is balanced and symmetrical in three-phase load

In binary linear equation, can the coefficient of the unknown be negative

The coefficient of the unknown can be negative, but it can't be 0. If it's not quadratic, it can be 0

Factorization 2x ^ 2-5xy-3y ^ 2-x-11y-6

Is that right?

Let u = {2,4, a & # 178; - A + 1}, a = {2, | a + 1}, CUA = {7}, find the value of A

a=3.

It is known that the definition domain of function f (x) = 2asin (2x - π / 3) + B is [0, π / 2], the maximum value of function is 1, and the minimum value is - 5

(1) Firstly, according to the definition domain of X, the range of (2x - π / 3) is calculated as (π / - 3,2 π / 3). By drawing the image of sine function, we can get the minimum value of the original function at π / - 3 and the maximum value at π / 2
(2) So we get 2A + B = 1, negative radical 3A + B = - 5. We can solve a and B, and we need not talk about the result. Let's move our hands. We can also see my solution: ∵ x ∈ [0, π / 2]; (2x - π / 3) ∈ [- π / 3, 2 π / 3]
When x ∈ [0, π / 2], sin (2x - π / 3) ∈ [- √ 3 / 2,1] is an increasing function
When a > 0, f (x) ∈ [- √ 3A + B, 2A + b]
The maximum value of ∵ function is 1, and the minimum value is - 5 ∵ 3A + B = 1, 2A + B = - 5 ∵ a = - 6 / (2 + 3) < 0
∴a＜0 ∴f(x)∈[2a＋b,﹣√3a＋b] ∴﹣√3a＋b＝﹣5 2a＋b＝1
A = 6 (2 - √ 3) B = 12 √ 3-23 wish you a happy study

When the vertex of parabola y = x & sup2; - 2mx + 4m + 5 is the highest, the value of real number m is

A parabola can be transformed into a parabola
y=(x-m)²-m²+4m+5
The ordinate of the vertex is - M & sup2; + 4m + 5
-m²+4m+5=-(m-2)²+7
So when m = 2, the vertex of parabola y = x & sup2; - 2mx + 4m + 5 is the highest

The rational number ABC is not zero, and a + B + C = 0, let x = |a | - B + C = |b | - A + C = |c | - A + B, try to find the value of the algebraic formula x ^ 19-99x + 2098
I'm here to ask you again···

(B + C) so, (B + C) (B + C) x = [a; (a + C) x; (a + C) x =; (a + C) x =; (a + C) x =; (a + C) x =; (B + C) / (b (B + C) = [b | / (a + C) / (a + C) / (A / b (a + C) / (a + B + C) x = [b (b (A / B / (a + C) / (a) so, 2 (a + B + B + C) 2 (2 (a + B + B + C) 2 (2 (a + B + B + B + C) 2 (2) 2) 2 (2 (2 (a + B + B + B + B = 0) because [a 124thereis no contradiction between them

(1200 + 1.4x) / (1000 + x), what is the maximum value of X?

(1200+1.4X)/(1000+X)
=（1400+1.4X-200）/(1000+X)
=1.4-200/(1000+X)
When x = infinity, the score is the largest
=1.4