How to calculate the expression 14 / 2-2 ^ 3 * 7 Mod 6

How to calculate the expression 14 / 2-2 ^ 3 * 7 Mod 6


7-8*7mod6
=7-56mod6
=7-2
=5
Arithmetic order:
Exponential operation (^)
Negative number (–)
Multiplication and division (*, /)
Integer division (\)
Modular operation (MOD)
Addition and subtraction (+, -)



Expression 1.5 + 3 / 2 > 2 or 7 Mod 3


1.5+3\2 = 1.5+1>2 true
7 mod 3 = 1 < 4 true
not 1 false
Finally: true or true and false = true
The answer is a, C
Because in VB, 0 = false, not 0 = true



VB programming, calculating the value of the expression 1 + X / 2! + x ^ 2 / 4! + x ^ 3 / 6! +. X ^ n (2n)!


Private Sub Command1_ Click()
Dim n As Long,x As Single,y As Single,y2 As Single,sum As Single
X = Val (InputBox ("please input a value):" input "," 0.1 "))
n = 1:y = 1:sum = 1
Do
y2 = y :y = y * x / n / (n + 1) :sum = sum + y :n = n + 2
Loop Until Abs(y2 - y) < 0.0000000001
Print sum
End Sub



5 / 18:10 / 27 reduction ratio


5/18:10/27
=5/18×27/10
=27/36
=3/4



Intelligent ABC symbol
How to type this symbol


Enter V3 space, the first on the second page



Simple algorithm of 1234 × 2345-1233 × 2346


1234×2345-1233×2346=(1233+1)*(2346-1)-1233*2346=2346-1233-1=1112
Adopt



Given the set a = {x ∈ R | 12 < 2x < 8}, B = {x ∈ R | - 1 < x < m + 1}, if a sufficient and unnecessary condition for X ∈ B is x ∈ a, then the value range of real number m is ()
A. m≥2B. m≤2C. m>2D. -2<m<2


A sufficient and unnecessary condition for a = {x ∈ R | 12 < 2x < 8} = {x | - 1 < x < 3}, ∵ x ∈ B is that x ∈ a, ⊊ B, ⊊ m + 1 > 3, that is, m > 2



Given X-1 / x = - 2, find the value of x ^ 2 of x ^ 4 + x ^ 2 + 1
First simplify, then evaluate: (X-Y 1 + X + Y 1) divide x ^ 2-y ^ 2 by XY, where x = √ 3 - √ 2, y = √ 2


1. Because (x ^ 4 + x ^ 2 + 1) / x ^ 2 = x ^ 2 + 1 / x ^ 2 + 1 = (x-1 / x) ^ 2 + 2 + 1 = (- 2) ^ 2 + 2 + 1 = 7
So x ^ 2 / (x ^ 4 + x ^ 2 +) = 1 / 7
2. (1 / X-Y + 1 / x + 1 / y) divided by x ^ 2-y ^ 2 / XY
=[(x+y)+(x-y)]/(x^2-y^2) ÷[xy/(x^2-y^2)]
=2x/(x^2-y^2)÷[xy/(x^2-y^2)]
=2/y
=2 / radical 2 = radical 2



Given that the solution of equation 4 + 5x = 2x + 1 is the same as that of equation x + 3 | a | = 5-9x, the value of a is obtained


4+5x=2x+1
∴5x-2x=1-4
∴3x=-3
∴x=-1
Substituting x = - 1 into x + 3|a| = 5-9x
have to
-1+3|a|=5+9
∴3|a|=15
|a|=5
A = 5 or - 5



1. Simplification: 4 / (x ^ 2-16) divided by 2 / (x-4) + X / (x + 4)
2. Calculate {a + 2 / (a ^ 2-2a) + 8 / (4-A ^ 2)} divided by A-2 / A


Simplify: 4 / (x ^ 2-16) divided by 2 / (x-4) + X / (x + 4) = 4 / (x + 4) (x-4) × (x-4) / 2 + X / (x + 4) = 2 / (x + 4) + X / (x + 4) = (x + 2) / (x + 4) enchanted mantra H2. Calculate {a + 2 / (a ^ 2-2a) + 8 / (4-A ^ 2)} divided by A-2 / a = A & # 178; / (A-2) + 2 / (A-2) & # 178; - 8A / (a + 2) (A-2) & # 178; = (A &