Let K be an integer and the solution of the equation KX about X equal to six minus 2x be a natural number

Let K be an integer and the solution of the equation KX about X equal to six minus 2x be a natural number

kx=6-2x
kx＋2x=6
x(k＋2）=6
k＋2=6/x
k=6-2x/x
Because K is a positive integer
So 6-2x > 0
x＜3
Because K is a positive integer
So k = 2 or 1

If K is an integer and the solution of the equation KX = - 5 about X is a natural number, then K=______ ．

The solution of the equation KX = - 5 about X is a natural number, and the value of K can be: - 1, - 5. So the answer is: - 1 or - 5

If the solution of the equation KX = 3 of X is a natural number, then the integer k is equal to?
Why not - 1 and - 3?

Because K is not zero,
So x = 3 / K
Because x is a natural number and K is an integer,
So k > 0 and divisible by 3,
Therefore, k = 1 or 3

Asin, ACOS, atan (A / b) are radians. Sin, cos, Tan (x °) are angles

The front is radian, the back is function, and the value is number

What is 7.8 times 2 / 9

78 out of 45, about 1.73

The area of a parallelogram billboard is 12.2 square meters, the bottom is 17 / 5, how high is it?
Using the equation solution,

Is it 5 / 17 meters? If so, it's easy to do
Set the height as X meters
5 / 17x (multiply sign) x = 12.2
Just ask for X

It is known that the image vertex of quadratic function is (- 1,2) and passes through (1, - 3), then the analytic expression is, why

The graph vertex of quadratic function is (- 1,2). Let the analytic expression of the function be y = a (x + 1) ^ 2 + 2
Because (1, - 3), so - 3 = a (1 + 1) ^ 2 + 2, the solution is a = - 5 / 4
The analytic expression of the function is y = - 5 / 4 (x + 1) ^ 2 + 2

I broke down If the quadratic trinomial 3x ^ 2 + 6x + m + 1 is a complete square, what is the value of M?
Why is the answer 3
I'm really two years old

3x^2+6x+m+1=(ax+b)^2
a^2=3
2ab=6
b^2=m+1
b^2=9/a^2=3=m+1,m=2

How to draw a triangle whose perimeter is equal to 7 + √ 13 in a square with one side so that its vertex is on the grid

Let F1 and F2 be the two focuses of hyperbola x2 / a2-y2 / B2 = 1 (a > 0, b > 0), if F1, F2, P (0, 2b) are the three focuses of an equilateral triangle
What is the eccentricity of the hyperbola

According to the meaning of the title:
2c：2b=2：√3
∴b=√3c/2
∴b²=3c²/4
∴e²=c²/a²
=c²/(c²-b²)
=c²/(c²/4)
=4