The solution equation: (1) 4 (x + 1) - 2 (x-3) = 18 (2) 1-x-34 = 2x-56

The solution equation: (1) 4 (x + 1) - 2 (x-3) = 18 (2) 1-x-34 = 2x-56

The final (1) 4 (x + 1) - 4 (x + 1) - 2 (x-3) - 2 (x-3) = 18 & amp; nbsp; 4 (x + 1) (2-2 (x-3) (2-2 (x-3) (x-2-2-2 (x-3) in the final (18-2-2 (x-3-2 (x-3-3) in the (1) 4 (4 (x + 1) - 4 (x + 1) - 2 (X-2 (x-2-2-2 (x-3) (2-2 (x-3) (2-2-2-2-2-2-2 (x-3) (2-2-2-2-2-2-2-3) (2-2-2-3) (2-2-2-2-2-2-2-3) (2-2-2-3) as (x-2-2-2-2-2-3) as (x-2-2-2-2-2-3) as-2-2-2 nbsp; x + 5 = 9 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp;          x+5-5=9-5                      x=4（2）1-x-34=2x-5612-3（x-3）=2（2x-5）    12-3x+9=4x-10      21-3x=4x-10   21+3x-3x=4x+3x-10   7x+10-10=21+10      7x÷7=31÷7          x=437

It is known that in ∠ ABC, D is a point on the bisector of ∠ ABC, e and F are on the sides AB and AC respectively, and de = DF. (points D, e and F do not coincide with point B) judge the relationship between ∠ bed and ∠ BFD, and explain the reason

The reason is as follows: as shown in the figure, DM ⊥ AB is in M, DN ⊥ BC is in N, and ⊥ DEM and △ DFN are right triangles. ∵ BD is the bisector of ∵ ABC, DM = DN. In RT △ DEM and RT △ DFN, de = DFDM = DN, ≌ RT △ DEM ≌ RT △ DFN (HL), ≌ RB ≌ DT ≌ DFN (HL) and ≌ RB ≌ DT ≌ DFN are right triangles

Is the N + 1 power of X multiplied by the N-1 power of X divided by the square of the n power of x = 1; (- 1 / 100) to the 0 power of (1000) to the 0 power equal?

Equal to the N + 1 power of X multiplied by the N-1 power of x = the 2n power of X multiplied by the power of the base number, and the base number added exponentially
For example, the square of the square of 2 is equal to the fourth power of 2, so their division is equal to 1
The second is because any non-zero real number to the power of 0 is equal to 1

Mathematical problem: how to find the inverse function of y = log a (x ^ 2-1 under x + radical) (a > 0, a is not equal to one)? Detailed process
Mathematical problem: how to find the inverse function of y = log a (x ^ 2-1 under x + radical) (a > 0, a is not equal to one)? Detailed process

Inverse solution
a^y=x+√(x²-1） (1)
∴a^y=1/(x-√(x²-1））
I.e. 1 / A ^ y = x - √ (X & sup2; - 1) (2)
(1) + (2) get
a^y+1/a^y=2x
x=a^y/2+1/(2a^y)
The inverse function is y = a ^ X / 2 + 1 / (2a ^ x)

Which is bigger, table tennis or the earth?
Every point on the earth has a corresponding point on table tennis, so I think they are the same size

If we compare the number of points, there are countless points in table tennis
There are countless points on the earth (because the concept of point itself is vague, there is no size, and it is a quantity that does not exist in reality and must be used). Since there are countless points, it is impossible to compare. This is the number of points. If it is larger than the volume, of course, it is the earth. The definition of volume is the size of the space occupied by the earth. Of course, the space occupied by the earth is larger than that of table tennis, That is, the volume of the earth is larger than that of table tennis
Therefore, the answer should be classified
Comparison points: unable to compare
Size: the earth is bigger than table tennis

It is known that the effective value of a sinusoidal AC voltage is 100V, the frequency is 50 Hz, and the initial phase is 30 degrees

The effective value of sinusoidal AC voltage is 100V, so the maximum value u m = 100 √ 2
The initial phase is 30 degree = π / 6, ω = 2 * π * f = 2 * 3.14 * 50 = 314
Analytical formula: u = 100 √ 2 sin (ω T + π / 6) = 100 √ 2 sin (314T + π / 6)

Let a be contained in B, a in C, and B {0,1,2,3,4,7,8}, C {3,4,7,9}, then the number of sets a satisfying the condition is several

Empty set, {3}, {4}, {7}, {3,4}, {3,7}, {4,7}, {3,4,7}
8 in total

As shown in the figure, C, D and E are the three points on the line AB, and AC = half of CD, e is the midpoint of BD, de = one fifth, ab = 2. Find the length of Ce (using straight line, ray and line)

AB=2
DE=BE=1/5
AD=AB-DE-BE=8/5
AC=AD/3=8/15
CE=AB=AC=BD=2-8/15-1/5=27/15

Let a be a symmetric matrix of order n and B be an antisymmetric distance matrix of order n. It is proved that: 1. AB minus Ba is a symmetric distance matrix; 2. AB plus Ba is an antisymmetric distance matrix

The meaning of symmetric matrix is that a is equal to its transpose matrix a ': a = a'
The meaning of antisymmetric matrix is that a and its transpose matrix add up to 0, that is a = - a '
On the transpose of matrix, there is the principle of strip, that is: (AB) '= b'a', (a + b) '= a' + B '
Let's use the definition and the third to prove the problem
Transposition of ab-ba: (ab-ba) '= (AB)' - (BA) '= b'a' - a'B '[the above is obtained from the principle of strip] = (- BA) - (a (- b)) [the above is determined by the definition of symmetric antisymmetry of a and b] = ab-ba
Therefore, the transpose of ab-ba is just equal to itself, which is a symmetric matrix
Transpose of AB + Ba: (AB + BA) '= (AB)' + (BA) '= b'a' + a'B '= - Ba + a (- b) = - (AB + BA)
The first two equal signs are obtained from the principle of strip, the third one is determined by the properties of a and B, and the last one is consolidation
Look at both sides of the equal sign, the transpose of AB + Ba is equal to the negative itself. From the definition, it can be seen that it is an antisymmetric matrix

The position relationship between line and circle
The end points of line segment AB with fixed length of 4 move on x-axis and y-axis respectively, and the equation of midpoint m in AB is obtained

Let m (x, y), then a (2x, 0) B (0,2y)
|AB|=4=√（4x²+4y²)
The simultaneous squaring of both sides is reduced to X & sup2; + Y & sup2; = 4
That is, the circle with the origin as the center and 2 as the radius