Equation: 4x + 4 / 5 = 22 / 5 x - 2 / 5

Equation: 4x + 4 / 5 = 22 / 5 x - 2 / 5

What is the equation 3 (x-3) = 18?

Divide two sides by three
x-3=18÷3=6
transposition
x=6+3
x=9

If f (x) and G (x) are odd functions, H (x) = AF (x) + BG (x) + 2, and there is a maximum value of 5 in the interval (0, + OO), then the minimum value of H (x) in the interval (+ OO, 0) is -

(x) - 2 = AF (x) + BG (x) is an odd function with a maximum value of 3 on the interval (0, + OO)
So the minimum value of H (x) - 2 in the interval (+ OO, 0) is - 3
So the minimum value of H (x) in the interval (+ OO, 0) is - 1

We know that a vector = (sin squared x, root 3 times cosx)
B vector = (1, SiNx)
Let f (x) = a vector · B vector
Finding the expression of F (x)

F (x) = a * b = sin ^ x + radical 3 * cosxsinx
=Sin square x + 2 / 2 root sign 3 * sin2x

If point O is a point in △ ABC, and the distance from point O to three sides is equal, ∠ BOC = 6150 °, then what is the degree of ∠ BAC
The problem is wrong. It should be
If point O is a point in △ ABC, and the distance from point O to three sides is equal, ∠ BOC = 150 °, then what is the degree of ∠ BAC
This is a multiple choice question A60 degree B90 degree C120 degree D150 degree

∠BOC＝150°
The distance between ∵ O and △ ABC is equal
Ψ ob bisection ∠ ABC, OC bisection ∠ ACB
∴∠CBO＝∠ABC/2,∠BCO＝∠ACB/2
∴∠BOC＝180-（∠CBO+∠BCO）
＝180-（∠ABC+∠ACB）/2
＝180-（180-∠BAC）/2
＝90+∠BAC/2
∴90+∠BAC/2＝150
∴∠BAC＝120°
The math group answered your question,

Solving practical problems with unknowns
A guard of honor formed a square array. In the first time, there were several people, but there were more than 100 people. In the second time, there were three more people and 29 less than in the first time. What was the total number of the guard of honor?

Let the number of rows and columns of a square matrix be X
X square + 100 = (x + 3) square - 29
X = 20,
So the total number of honor guards is 20 * 20 + 100 = 500

It is known that △ ABC is inscribed in the circle O: x ^ 2 + y ^ 2 = 1 and 3oa vector + 4ob vector + 5oC vector = 0
If ∠ xoa = - π / 4, if the ray ox is the starting edge and the ray OC is the ending edge, it is called α. The value range of α and the coordinates of point C are calculated

From the known: | OA vector | = | ob vector | = | OC vector | = 1.3oa vector + 4ob vector + 5oC vector = 0, that is, 3oa vector + 4ob vector = - 5oC vector, the square is: (3oa + 4ob) ^ 2 = (- 5oC) ^ 2, that is, 9 + 16 + 24oa * ob = 25. Then: OA * ob = 0, OA is perpendicular to ob. ∠ xoa = - π / 4, so the coordinate of point a is (√ 2 / 2, √ 2 /

As shown in the figure, △ ABC, e is the midpoint of BC, de ⊥ BC in E, DM ⊥ AB in M, DN ⊥ AC in N, BM = CN. Try to prove that point D is on the bisector of ∠ BAC

It is proved that: as shown in the figure, connecting BD and CD, ∵ de ⊥ BC, e is the midpoint on the edge of BC, ∵ BD = CD, in △ BDM and △ CDN, BD = cdbm = CN, ≌ BDM ≌ CDN (HL), ≌ DM = DN, and ∵ DM ⊥ AB, DN ⊥ AC, ≁ point D is on the bisector of ∠ BAC

When k takes what value, the square + X of the equation 2x / (x + 1) - (x + 1) / x = K / x will produce an increasing root?

2X / (x + 1) - (x + 1) / x = K / (x ^ 2 + x) multiplied by x ^ 2 + X 2x ^ 2 - (x + 1) ^ 2 = k, x ^ 2-2x-1-k = 0. For example, when x = 0 or x = - 1, the solution of the equation has an increasing root, when x = 0, k = - 1, when x = - 1, k = 2, so when k = - 1 or 2, it has an increasing root

Point a and B are the left and right ends of the major axis of the ellipse x236 + y220 = 1, point F is the right focus of the ellipse, point P is on the ellipse and above the x-axis, PA ⊥ PF

From the known point a (- 6,0), f (4,0), let the coordinates of point p be (x, y), then AP = {x + 6, y}, FP = {x − 4, y}, from the known point x236 + y220 = 1 (x + 6) (x − 4) + y2 = 0, then 2x2 + 9x − 18 = 0, x = 32 or x = - 6. Since Y > 0, only x = 32, then y = 523, the coordinates of point P are (32523)