20 festival lanterns form a series circuit, which is connected to the home circuit. What is the voltage at both ends of each lantern?

20 festival lanterns form a series circuit, which is connected to the home circuit. What is the voltage at both ends of each lantern?


The resistance of each small bulb should be the same, so divide 220 V by 20 to get 11 v



If the result of (x cube MX n) * (x square - 5x 3) does not contain the cubic and quadratic terms of X, then what relation should m and N satisfy?


The formula given is not clear
In general, the solution of this kind of problem is to expand the original formula and arrange it according to the power of X, and then determine the coefficient before x according to the requirements
For example, the coefficient before the third and second terms of X is 0. Through calculation, the relationship between M and N is finally calculated



The watt hour meter is marked with "3000r / kW · H". When a single consumer is used, the watt hour meter turns 5R for 100s, then the electric power of the consumer is?


P=1kWh/3000 ×5÷ 1/36h=0.06kW=60W



X ^ 2 + 3 radical 3 + 4 = 0, how much is X1? How much is x2? Why can't I calculate it with B ^ 2-4ac?


The root formula is: [- B ± root sign (b ^ 2-4ac)] / 2A



Which single-phase meter turns faster when the power consumption of 3 (12) a 2400r / kWh and 5 (10) a 1200R / kWh is the same?
For example: single phase watt hour meter - 3 (12) a 2400r / kWh and 5 (10) a 1200R / kWh with the same electricity consumption, which watt hour meter turns faster? It means: like turning on a 100 watt electric light, which watt hour meter turns to 1 kilowatt hour faster? I rent a house, and I'm worried that the landlord will have to pay a lot more electricity charges because of turning on a low-power watt hour meter. Please reply to my question?


In terms of speed, of course, the 2400r / kWh meter turns faster than the 1200R / kWh meter! But if the error is not taken into account, the power consumption is the same, that is, to turn on a 100 watt lamp, two meters should turn to 1 kilowatt hour at the same time!
However, the general meter has errors, and the error is large when the power consumption is 15%, which is usually slow! From this point of view, the large meter will pay less electricity charges, which is reflected in the small load work! (compared with the small meter, the small load range of the large meter becomes larger)



Factorization 2x & # 178; - 2x-3


2x²-2x-3
quadratic formula
X = 2 ± root (4 + 24) / 4
=(1 ± root 7) / 2



The relative atomic mass of a divalent metal element is ()
A. 24B. 40C. 56D. 64


Suppose that the metal element is r, the mass of metal oxide is x.ro → R, the transfer electron is 1mol 2molx & nbsp; & nbsp; & nbsp; 0.2molx = 0.1mol, the molar mass of metal oxide is 4g0.1mol = 40g/mol, the relative molecular mass of metal oxide is 40, so the relative atomic mass of metal atom is 40-16 = 24, so a



What is the simple formula for 75.6 - (14.3-8.3)?
Simple formula of 75.6 - (14.3-8.3)
Quick answers


Simple formula of 75.6 - (14.3-8.3)
=75.6-6
=69.6;
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In a series circuit, the electric power of resistor 1 is 0.1W, the resistance value of resistor 2 is 20 Ω, and the power supply voltage is 3V


I^2*R1=0.1
I*(R1+20)=3
Results: I = 0.05, R1 = 40
Or: I = 0.1, R1 = 10
Then R2 electric power is 0.05W or 0.2W



limn→∞ 1/n^3(1²+2²+...+n²)