Simple calculation of 5 / 11 × 6 / 17 + 5 / 17

5 / 11 × 6 / 17 + 5 / 17
=6/11x5/17+5/17
=(6/11+1)x5/17
=17/11x5/17
=5/11
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Simple mathematical calculation: 17 / 20 × 7 / 17 - 1 / 20 × 17 / 3
Off type: 8.1 △ [(4 and a quarter - 700 × 0.5%) / 1 and a half]

17 / 20 × 7 / 17 - 1 / 20 × 17 / 3
=7/20-17/60
=4/60
=1/15
8.1 △ [(4 and a quarter - 700 × 0.5%) / 1 and a half]
=81/10÷【(17/4-14/4)÷3/2】
=16 and 1 / 5

Simple calculation of 7:25 17 - (4:35 29-2:25 8) + 5:35 1

7:25 17 - (4:35 29-2:25 8) + 5:35 1
=7,25:17-4,35:29 + 2,25:8 + 5,35:1
=(17 of 7 and 25 + 8 of 2 and 25) + (1 of 5 and 35-4 of 35-29)
=10 + 7 / 35
=10 and 7 / 35

It is known that the function y = f (x) with continuous image has a unique zero point in the interval (a, b) (B-A = 0.1). If the approximation of the zero point (accurate to 0.001) is obtained by dichotomy, then the degree of dividing the interval (a, b) into equal parts is at least?

Using one-time dichotomy, the interval length becomes half of the original,
Therefore, the interval length constitutes an equal ratio sequence with 0.1 as the first term and 0.5 as the common ratio, and the nth term is required to be less than or equal to 0.001
That is, 0.1 * 0.5 ^ (n-1) = 100
So n > = 8 is OK

What is the condition that the intersection point of parabola and X axis is on the same side or both sides of the origin
-If the discriminant of 3x2-x + M = 0 is greater than 0, then the intersection point of the parabola y = - 3x2-2 + m and X axis is on the same side or both sides of the origin
In addition, when y = x2-2 (K + 2) x + 2 (K + 1), what is the value of K, the intersection of parabola and X axis is on the same side of Y axis. The answer given by the teacher is (K + 1) > 0,

-3x^2-x+m=0
(-1)^2-4*(13)*m
If the above formula is greater than 0, there will be 2 intersections; if it is equal to 0, there will be 1 intersection; if it is less than 0, there will be no intersection
When it is greater than 0, 1 + 52m > 0
m>(-1/52)
At this time, the original formula is solved to see whether the hypothesis is true

As shown in the figure, the intersection point m (0,3) of the line L: y = 1 / 4x + B and Y axis, the vertex coordinates of a group of parabola are B1 (1, Y1), B2 (2, Y2), (B3, Y3). (BN, yn) (n is a positive integer), they are the points on the line in turn, the intersection points of this group of parabola and the positive half axis of X axis are A1 (x1,0) A2 (x2,0) A3 (x3,0). An + 1 (xn + 1,0) (n is a positive integer), let X1 = a (0)

(1) It is easy to find B = 3, Y1 = 13 / 4, let the parabolic equation be y = C (x-1) ^ 2 + 13 / 4, it passes through point A1, so C (A-1) ^ 2 + 13 / 4 = 0, C = - 13 / [4 (A-1) ^ 2], and the parabolic equation be y = - 13 / [4 (A-1) ^ 2] * (x-1) ^ 2 + 13 / 4
(2) For the n-th parabola from left to right, its vertex is (n, N / 4 + 3). If the n-th parabola and the x-axis are an, an + 1, then an + a (n + 1) = 2n (two points are symmetric about the symmetry axis), so a (n + 2) + a (n) = 2 (n + 1). By subtracting the two formulas, a (n + 2) - an = 2, and the sum of the distances between the n-th parabola and the x-axis is [a (n + 1) - an] + [a (n + 2) - a (n + 1)] = a (n + 2) - an = 2, Therefore, the sum of the distances between two adjacent parabolas and the two intersections of x-axis is always 2

2+(3x-1)/8>3-(x+7)/4

(3x-1)/8+(2x+14)/8>1
(3x-1)/8+(2x+14)/8-8/8>0
[3x-1+2x+14-8]/8>0
[3x-1+2x+14-8]>0
5x+5>0
x>-1

About 3 (X-Y) / (Y-X) ^ 2

3(x-y)/(y-x)^2
=3(x-y)/(x-y)^2
3/(x-y)

Is the average velocity formula △ x divided by △ t? Is the average velocity formula s divided by T? Please specify

The average speed refers to the ratio of the displacement of an object moving in a certain period of time to the time used. It is a vector with directivity. In other words, it represents the average speed of an object in the time interval △ t. △ s △ t = average speed or (V0 + VT) / 2 = average speed
The ratio of the distance an object passes through to the time it takes to pass through the distance is called the average speed on the distance. It is usually called the average speed, but it is quite different from the average speed. The average speed is the ratio of the displacement an object passes through to the time it takes to pass through the displacement

Binary linear equations: Y / 3 - x + 1 / 6 = 32 (x - Y / 2) = 3 (x + Y / 18)
Solution by addition and subtraction

Y / 3 - (x + 1) / 6 = 3 multiply both sides by 6 to get 2Y - (x + 1) = 18x-2y + 19 = 0 multiply both sides by 66x-12y + 19 * 6 = 0 (1) 2 (X-Y / 2) = 3 (x + Y / 18) simplify to 2x-y = 3x + Y / 6 multiply both sides by 6 to get 12x-6y = 18x + y 6x + 7Y = 0 (2) (1) - (2) - 19y + 19 * 6 = 0y = 6 (2) 6x + 7 * 6 = 0x = - 7

Simple calculation of 5 / 11 × 6 / 17 + 5 / 17