Let the equation of the line l be (a + 1) x + y-2-a = 0 (x ∈ R). If the intercept of the line L on the two coordinate axes is equal, the equation of the line L is obtained (1) the intercept of the line L (a + 1) x + y-2-a = 0 (x ∈ R) on the horizontal axis is & # 160; the intercept of a + 2 / A + 1 on the vertical axis is a + 2 Why is the intercept of a line on the horizontal axis a + 2 / A + 1 and a + 2 on the vertical axis

Let x = 0 be substituted into the equation, y = (a + 2), which is the intercept on y
Let y = 0 be substituted into the equation, x = (a + 2) / (a + 1), which is the intercept on X
They are equal, a + 2 = (a + 2) / (a + 1), (a + 2) (1-1 / (a + 1)) = 0, (a + 2) a / (a + 1) = 0
A = - 2 or a = 0
When a = - 2, l is X-Y = 0
When a = 0, l is x + Y-2 = 0

How easy is 4.58 times 25.1 plus 45.8 times 6.35 plus 0.458 times 114

4.58×25.1+45.8×6.35+0.458×114
=4.58×25.1 +4.58×63.5+ 4.58×11.4
=4.58×（25.1+63.5+11.4）
=4.58×100
=458

If the line y = KX + B is parallel to the line y = - 2x + 1 and intersects with the line y = x-3 on the Y axis, then the analytical expression of the line y = KX + B is

First, k = - 2
If it intersects with y-axis, the intersection point is (0, - 3), and it is driven into the straight line y = - 2x + B, B = - 3
That is y = - 2x-3

It is known that the sum of the first n terms of the sequence {an} is Sn, and the point (n, Sn) is on the image of the function f (x) = - x ^ 2 + 3x + 2. 1 find the general formula of an. 2. If the first term of the sequence {BN an} is 1 and the common ratio is Q (Q ≠ 0), find the first n terms and TN of the sequence {BN}
...

an=Sn - Sn-1 = -n^2+3n+2 -[-(n-1)^2+3(n-1)+2]
=(n-1)^2-n^2+3n-3n-3+2-2
=(n-1+n)(n-1-n)-3
=2n-1-3
=2n-4
Let bn-an = q ^ (n-1), then BN = q ^ (n-1) - an = q ^ (n-1) + 2n-4
Then TN = Q

There are two point charges in vacuum, 30cm apart, and their charge quantities are + 2.0 × 10-9c and - 4.0 × 10-9c respectively. (k = 9.0 × 109n · m2 / C2) question: (1) is the interaction force between the two charges gravitational or repulsive? (2) What is the interaction between these two charges?

(1) Because the electric properties of the two charges are opposite, the Coulomb force between them is gravity, so the interaction between the two charges is gravity. (2) from Coulomb's Law: F = kqqr2, the data is: F = 8 × 10-7n, so the interaction between the two charges is: F = 8 × 10-7n The force is 8 × 10-7n

If there is a real solution to the equation | 1 + X | = MX, the range of M is

1+x=±mx
(1±m)x+1=0
(1±m)x=-1
x=-1/(1±m）
1±m≠0
±m≠1
m≠±1

Given that a and 2b are reciprocal to each other, - C and D2 are opposite to each other, | x | = 4, find the value of 4ab-2c + D + X4

According to the meaning of the question: 2Ab = 1, - C = - D2, x = ± 4, when x = 4, the original formula = 3; when x = - 4, the original formula = 1

The monotone decreasing interval of function y = 3x Λ 2-2x is

y=3x∧2-2x
=3(x²-2x/3)
=3(x-1/3)²-1/3;
When x ∈ (- ∞, 1 / 3], y decreases monotonically
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If (x ^ m ／ x ^ 2n) ^ 3 ／ x ^ M-N and - 1 / 4x ^ 2 are of the same kind, and 2m + 5N = 7, find the value of 25N ^ 2-4m ^ 2

It is reduced to 2m-5n = 2
Because 2m + 5N = 7
M = 9 / 4, n = 1 / 2
So 25N ^ 2-4m ^ 2 = - 14

Find the value range of 2x-x2 power of function y = 1 / 3

Let g (x) = 2x - x ^ 2, then y = (1 / 3) ^ g (x)
g(x) = -(x-1)^2 +1≤1
Y = (1 / 3) ^ g (x) is a monotone decreasing function
So when G (x) = 1, i.e. x = 1
Y has a minimum value, where y = 1 / 3
So the range of Y is y ≥ 1 / 3, X ∈ R