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The trip is about two hours
What to do
A and B leave from a and B respectively. The speed of a is 1.5 times that of B. five hours later, the two cars meet. At this time, a is 55 thousand kilometers above the terminal
Speed ratio of a and B = 1.5:1 = 3:2
When we meet, the first line is 3 / 5 of the whole course, and the second line is 2 / 5 of the whole course
Then the whole journey = 55 / (3 / 5-1 / 2) = 55 / (1 / 10) = 550 km
Speed of a = (550 × 3 / 5) / 5 = 66 km / h
B speed = 66 / 1.5 = 44 km / h
If 2 (4a-2) - 6 = 3 (4a-2), then a2-3a + 4=______ ．
2 (4a-2) - 6 = 3 (4a-2), 8a-4-6 = 12a-6, 8A-12A = 4, a = - 1, a2-3a + 4 = (- 1) 2 + 3 + 4 = 8
How many kilometers can a car travel in 5 hours?
Set five hours to travel x kilometers
2 / 64 = 5 / X
The solution is: x = 160
A: 160 kilometers in five hours
How to calculate the number of monomials?
How to calculate the number of monomials? I need to give more examples to understand. Give more examples of different types
The concept of the degree and coefficient of monomials and polynomials [1] monomials: Generally speaking, the monomials about what are called coefficients. For example, the monomials about XY; ABXY, the coefficients are ab. the degree is the sum of all the exponents about what. For example, the monomials about XYZ: 3axyz, the coefficients are 3a
There is a batch of cement on the construction site. 3 / 20 of it was used for the first time, and 5 tons more was used for the second time. At this time, there are 30 tons left. How many tons of this batch of cement?
Urgent, elementary school sixth grade mathematics application question, must list the formula
Suppose this batch of cement has x tons
3/20x+3/20x+5+30=x
3/10x+35=x
7/10x=35
x=50
A: this batch of cement is 50 tons
Right triangle ABC, angle c = 90 degrees, o point in the triangle, so that AOB, BOC, COA three triangles equal area
Find the ratio of (OA's Square) and (OB's Square), and (OC's Square)
When crossing AC BC to D E, OD = 1 / 3bC, OE = 1 / 3aC, and ceod is rectangular, so ad = 2 / 3aC, be = 2 / 3 BC.OA ^2 = (2 / 3aC) ^ 2 + (1 / 3bC) ^ 2ob ^ 2 = (2 / 3bC) ^ 2 + (1 / 3aC) ^ 2, so OA ^ 2 + ob ^ 2 = 5 [(1 / 3aC) ^ 2 + (1 / 3bC) ^ 2] = 5oC ^ 2
For a rectangular piece of paper with an area of 1 square meter, cut half of it in the first time and the remaining half in the second time. If so, what is the area of the remaining piece of paper after the fifth time?
The fifth power of the remaining 1 × (1-1 / 2) is 1 / 32 square meter
If the image of a linear function passes through points (2,5) and is parallel to the line y = - x + 1, then the analytic expression of the function is?
The graph of a function of degree passes through points (2,5),
And it is parallel to the line y = - x + 1, so the slope is - 1
Then the analytic expression of the function is set as y = - x-b
Substituting (2,5), B = - 7
y=-x+7
The number of male workers in the knitting factory accounts for 40% of the total number of workers in the factory, and the number of female workers is divided into three workshops, with an average of 60 people in each workshop?
60 × 3 (1-40%) = 300 people
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