Qiang Qiang, Wei Wei and Liang Liang are three good friends whose ages are three consecutive natural numbers They are 504 years old. Guess how old they are?

Qiang Qiang, Wei Wei and Liang Liang are three good friends whose ages are three consecutive natural numbers They are 504 years old. Guess how old they are?

504=2^3×3^2×7
³√504 ≈ 8
Distribution factor, these three continuous natural numbers are 7, 8, 9

Qiang Qiang, Wei Wei and Liang Liang are three good friends. They are just one year older than each other (three consecutive natural numbers). Their ages are multiplied by 504. Guess & nbsp; how old are they?

504 = 2 × 2 × 2 × 3 × 3 × 7 = 7 × 8 × 9; age is just three consecutive natural numbers, so the three people's ages are 7 years old, 8 years old and 9 years old respectively

Given that the solutions of the equation 3x + 2m = 9x + 1 and 6x + 1 = 2m + 3x are the same, then the value of M is
Given that the solutions of the equation 3x + 2m = 9x + 1 and 6x + 1 = 2m + 3x are the same, then the value of M is
a.-1/2 b.1/3 c.1/2 d.-1/3

C
From 3x + 2m = 9x + 1, we can get 6x + 1 = 2m, and the two solutions are the same, so 2m + 3x = 2m, we can get x = 0, and substitute 6x + 1 = 2m to get m = 1 / 2

A simple algorithm of 11 * 22 * 33 * 44.1999
Urgent need

(10+1)*(20+2)*(30+3).(1000+999)

The sum of the first three terms of the arithmetic sequence {an} is S3 = 15. If a1 + 1, A2 + 1 and A3 + 4 are equal ratio sequence, the general term formula an is obtained
Step by step

The sum of the first three terms of arithmetic sequence {an}
S3＝a1+a2+a3=15
That is, 3A1 + 3D = 15, a1 + D = 5,
∴a1=5-d
And a1 + 1, A2 + 1, A3 + 4 are equal ratio series
∴(a2+1)^2=(a1+1)(a3+4)
That is, (a1 + 1 + D) ^ 2 = (a1 + 1) (a1 + 2D + 4)
∴6^2=(6-d)(9+d)
∴d^2+3d-18=0
The solution is d = - 6 or D = 3
When d = - 6, A1 = 11,
an=17-6n
When d = 3, A1 = 2,
an=3n-1

How much is 4 / 5 * 9 / 7 * 8 / 5

Let's see if you write it correctly. If you write it correctly, I can only say that it can't be simplified. It's 288 / 175

The sequence {an} is defined as follows, A1 = 2, an + 1 = an ^ 2-An + 1, and 1 / A1 + 1 / A2 + 1 / A3 + +1/a2008

Symbol description: N in a [n] is a subscript. From the topic meaning, a [n + 1] - 1 = a [n] * (a [n] - 1) take the reciprocal on both sides of the equation, and get 1 / (a [n + 1] - 1) = 1 / (a [n] - 1) - 1 / a [n], then 1 / a [n] = 1 / (a [n] - 1) - 1 / (a [n + 1] - 1), for any positive integer n, then 1 / a [1] + 1 / a [2] + 1 / a [3] + +1/a[2008]=1/(a...

Choose three numbers from 2, 6, 7 and 5 to form a three digit number, which is the multiple of 3

267 276 762 726 672 627 675 657 765 756 567 576

It is proved that the necessary and sufficient condition for the row equivalence of matrix amxn and bmxn is the existence of invertible matrix P of order m such that PA = B

The main purpose of this topic is to understand what is line equivalence
Tongji 4th Edition p.59 is defined as follows:
If matrix A is transformed into matrix B by finite elementary row transformation, matrix A and B are said to be equivalent
(= >) necessity
Because row a is equivalent to row B
So a becomes a matrix B by finite elementary row transformation
So there are Finite Elementary Matrices P1, P2,..., PS such that p1p2... PSA = B
Let P = p1p2... PS, then it is reversible and satisfies PA = B
(

44. For a five digit number, the three digits on the left are five times of the two digits on the right. If the two digits on the right are moved to the front, the new five digit number will be 75 times more than the original five digit number, and the original five digit number will be ()
A.12525\x05\x05B.13527\x05\x05C.17535\x05\x05D.22545

A
The original five digit number is 13527, and the new five digit number is 27135;
The original five digit number is 17535, and the new five digit number is 35175;
The original five digit number is 22545, and the new five digit number is 45225;
The original five digit number is 12525 and the new five digit number is 25125