A rectangular food box is 8 cm long, 6 cm wide and 10 cm high. If a circle of brand paper is pasted around the food box, how many square meters is the area of the brand paper at least?

A rectangular food box is 8 cm long, 6 cm wide and 10 cm high. If a circle of brand paper is pasted around the food box, how many square meters is the area of the brand paper at least?


(8 × 10 + 6 × 10) × 2 = (80 + 60) × 2 = 140 × 2 = 280 (square centimeter); 280 square centimeter = 0.028 square meter



A rectangular iron food box, 12 cm long, 8 cm wide and 15 cm high. If a circle of brand paper is pasted along its side, what is the area of this brand paper
How many?


12×15×2+8×15×2
=360+240
=600 (square centimeter)



A circle of label paper is pasted around a rectangular food box with a length of 1 decimeter, a width of 8 cm and a width of 5 decimeters
The area of this brand paper is at least ()


This problem is equivalent to finding its surface area
①1dm=10cm
②1.5dm=15cm
③(10×5+8×5)×2=180cm²
④180+100=280cm²
Hope to adopt it~



Three fifths of a square meter equals () square centimeter


1㎡=10000c㎡
Three fifths square meter = 0.6x10000 = 6000 square centimeter



Nanjing Yangtze River Bridge, the lower railway bridge is 6772 meters long, of which the main river bridge is 1577 meters long. It took two minutes for a 300 meter long train to pass through the main river bridge? (2) How long does it take to cross the whole railway bridge at this speed?





As shown in the figure, in square ABCD, ab = 2, e and F are on BC and CD respectively, and CE = cf. if the area of triangle AEF is 1, find the length of EF


Let CE length be a, then the area of triangle AEF = 2 * 2-1 / 2 * 2 * (2-A) - 1 / 2 * 2 * (2-A) - 1 / 2 * A & # 178; = 1
That is a & # 178; - 4A + 2 = 0, the solution is a = 2 - √ 2
So EF = √ 2A = 2 (√ 2-1)



The speed of light propagation in vacuum is 3.0 X10 to the eighth power meters per second. How many kilometers is 1 light year (365 days) (the distance of light propagation in a year) equivalent to?
Please advise!


365 * 24 * 60 * 60 * 3 * 10 ^ 8 = 9460 billion km



A mobile communication company carries out two kinds of services: the users of "global" pay 50 yuan monthly rent, and then pay 0
A mobile communication company carries out two kinds of services: "global" users pay 50 yuan monthly rent, and then pay 0.4 yuan for each minute of the call; "Shenzhouxing" does not pay the monthly rent, and pays 0.6 yuan for each minute of the call
(1) How much is the cost of the two methods expressed in algebraic form?
(2) For a certain call time, will the two modes cost the same amount?
3) If someone estimates that they can talk for 300 minutes in a month, which way is more cost-effective?


(1) Assuming that the cost of global communication is Y1 and the cost of China travel is Y2, we get the following results:
Y1=50+0.4X
Y2=0.6X
(2) Let Y1 = Y2, that is, 50 + 0.4x = 0.6x
It is calculated that x = 250, that is, the cost of the two methods is equal when the call is 250 minutes
(3) Substituting x = 300 into the two equations, Y1 = 50 + 0.4 * 300 = 170 can be obtained
Y2=0.6*300=180
So Y1



In diamond ABCD, AC = 8cm, BD = 6cm, then the area of diamond is______ .


∵ AC = 8cm, BD = 6cm, the area of rhombus = 12ac · BD = 12 × 8 × 6 = 24cm2



Solving equation x square + 6x-360 = 0


X square + 6x-360 = 0
x²+6x+9=369
(x+3)²=369
∴ x+3=±3√41
Ψ x = - 3 + √ 41 or x = - 3 - √ 41