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A rectangular glass container, 8 decimeters wide, now 45 cm deep, when a square iron block with an edge length of 4 decimeters is placed in the water After that, will the water overflow? If so, how many liters?
Hello:
45 cm = 4.5 decimeters
Free space of glass container = 10 × 8 × (5-4.5) = 40 (cubic decimeter)
Cube volume = 4 × 4 × 4 = 64 (cubic decimeter)
64 cubic decimeter > 40 cubic decimeter
So, the water will overflow
Overflow volume = 64-40 = 24 (cubic decimeter) = 24 (liter)
A cube iron block with 10 cm edge length is immersed in a rectangular water tank. The length of the water tank is 40 cm, the width is 20 cm, and the water depth is 25 cm. After taking out this iron block, what is the distance between the water surface and the bottom of the tank?
Volume of cube: 10 × 10 × 10 = 1000 cubic centimeter
Bottom area of water tank: 40 × 20 = 800 square centimeter
Take out this iron block, the height of water surface reduction: 1000 △ 800 = 1.25 cm
The distance between the water surface and the bottom of the box is 25-1.25 = 23.75 cm
120 / x + (6x-120) / ((1 + 25%) x) = 6-2 / 3 to solve the equation
120/x+(6x-120)/((1+25%)x)=6-2/3
150+6x-120=(20/3)x
(2/3)x=30
x=45
What is the formula of area, surface area and volume of triangle?
Area bottom × height / 2
If cos (a + π / 3) = 1 / 3, a is an acute angle, cosa can be obtained
cosa
=cos[(a+π/3)-π/3]
=cos(a+π/3)cosπ/3+sin(a+π/3)sinπ/3
=(1/3)*(1/2)+(2√2/3)*(√3/2)
=(1+2√6)/6.
Solution equation: 23 (2x-1) - 12 (2x-1) = 15
If we remove the denominator, we get 20 (2x-1) - 15 (2x-1) = 6, that is, 5 (2x-1) = 6, if we remove the brackets, we get 10x-5 = 6, and the solution is x = 1.1
Finding the maximum and minimum of the square of quadratic function y = 3x
y=3x^2≥0
So the minimum value is 0
The maximum value is positive infinity
It can also be concluded by drawing
The quadratic function is a parabola with the opening upward and the vertex coordinate as the origin
Square ABCD, AC as the focus, and the eccentricity of ellipse passing through B is
If the side length of the square is 1, then AC = √ 2, and AC is the focus, then the focal length of the ellipse, 2C = √ 2, C = √ 2 / 2, and because the ellipse passes through point B, the axis of AC must be the major axis (the axis of focus), so B is on the minor axis, and is a vertex of the minor axis
2.1 * 3.6 * 1.6 * 8.4 how to calculate with simple method
2.1*3.6*1.6*8.4
=(2+0.1)*3.6*1.6*(10-1.6)
=(7.2+0.36)*(16-2.56)
=7.56*13.44
=(8-0.44)*(13+0.44)
=104-5*0.44-0.44*0.44
=104-0.44*5.44
=104-2.3936
=101.6064
What is the fraction of 17 / 2 in formula 1.8? 2. 3 / 2 times of a number is 2 more than 2 / 5 of 5 / 2. Find the number! (solve the equation)
The second problem is solved by equation
1、8÷17/2=16/17
2. Let the number be x and the equation be
3/2X-5/2×2/5=2
X=2
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