A 16 cm long and 8 cm wide rectangular sheet iron, can you cut it into five pieces and weld it into a rectangular container with a square bottom? (no waste) draw a sketch and figure out the volume of the container?

A 16 cm long and 8 cm wide rectangular sheet iron, can you cut it into five pieces and weld it into a rectangular container with a square bottom? (no waste) draw a sketch and figure out the volume of the container?

The drawing is as follows: the volume of the container is 8 × 8 × 2 = 128 (cubic centimeter). A: the volume of the container is 128 cubic centimeter

A 16 cm long and 8 cm wide rectangular sheet iron, can you cut it into five pieces and weld it into a rectangular container with a square bottom? (no waste) draw a sketch and figure out the volume of the container?

The drawing is as follows: the volume of the container is 8 × 8 × 2 = 128 (cubic centimeter). A: the volume of the container is 128 cubic centimeter

Prove: in triangle ABC, ACOS ^ 2C / 2 + bcos ^ 2A / 2 = 1 / 2 (a + B + C)

Sports club or sports club?

sports club
Sports should be plural when it means sports, such as sports meeting

Known: as shown in the figure, take both sides AB and AC of known triangle ABC as edges, make equilateral triangle abd and triangle ace outward, DC and be intersect at point o
(1) Verification: DC = be;
(2) Calculate the degree of BOC;
(3) When the degree of angle BAC changes, does the angle BOC change? If not, ask for the size of the angle BOC; if it changes, please explain the reason?
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∵ abd and ace are equilateral triangles
∴AD=AB,AC=AE
∠DAB=∠CAE=60°
Then, DAC = DAB + BAC = 60 ° + BAC = CAE + BAC = BAE
In △ DAC and △ BAE
AD=AB,∠DAC=∠BAE,AC=AE
∴△ABD≌△ACE
∴∠ADC=∠ABE
Then, BOC = ODBC + OBD = ODBC + Abe + abd = ADB + abd = 60 ° + 60 ° = 120 °

The greatest common divisor of two numbers is 8, and the least common multiple is 48. How many are these two numbers?

8 and 24

In △ ABC, if cosa = √ 3 / 2, and a: B = 1: √ 3, C = 4, the area of the circle is

a: B = 1: √ 3 let a = t, B = root sign 3 t be brought into T ^ 2-6t + 8 = 0 by cosine theorem cosa = (b ^ 2 + C ^ 2-A ^ 2) / 2BC = √ 3 / 2. When t = 2 or T = 41, t = 2, triangle is right triangle, C is hypotenuse inscribed circle, radius is R (a + B + C) R / 2 = a * B / 2R = (3 - √ 3) / 2, area s = π R ^ 2 = π (6-3

Please write down prime numbers within 20______ ．

Prime numbers within 20 are: 2, 3, 5, 7, 11, 13, 17, 19. So the answer is: 2, 3, 5, 7, 11, 13, 17, 19

If the intersection of the lines Y1 = K1X + 4 and y2 = k2x-2 is on the x-axis, then K1: K2 is?

Y = 0 on X-axis
That is, when y = 0, two X are equal
y1=k1x+4=0
x=-4/k1
y2=k2x-2
x=2/k2
So - 4 / K1 = 2 / K2
So 2K1 = - 4k2
k1:k2=-2

Make the following sentences plural
(1)I am a student.
(2)This is my frind
(3) She is a customs office
(4) My case is brown
(5)What colour is her hat?
(6)Is this your blouse?
(7)Here is my possport.
(8)Whose shirt is this?
(9)It is an English car.
(10) He is an engineer

(1)I am a student.
We are students.
(2)This is my frind
These are our friends.
(3) She is a customs office
They are coustoms offices.
(4) My case is brown
Our cases are brown.
(5)What colour is her hat?
What colour are their hats?
(6)Is this your blouse?
Are these your blouses?
(7)Here is my possport.
Here are our possports.
(8)Whose shirt is this?
Whose shirts are these?
(9)It is an English car.
They are English cars.
(10) He is an engineer
They are engineers.