A cuboid water tank is immersed in a cube iron block with an edge length of 10 cm. The length of the water tank is 40 cm, the width is 30 cm, and the water depth is 25 cm. When the iron block is taken out, what is the distance between the water surface and the bottom of the tank?

A cuboid water tank is immersed in a cube iron block with an edge length of 10 cm. The length of the water tank is 40 cm, the width is 30 cm, and the water depth is 25 cm. When the iron block is taken out, what is the distance between the water surface and the bottom of the tank?


Volume of water = 40x30x25-10x10x10 = 29000 CC
The final result is: 29000 ÷ (40x30) = 24 and 1 / 6 cm



A cuboid water tank is 4 decimeters wide and 6 decimeters high. The water depth in the water tank is 2 decimeters. Put a cube with an edge length of 3 decimeters into the water tank,
How deep is the water in the tank?


(4 * 5 * 2 + 3 * 3 * 3) / (5 * 4) = 3.35 decimeters



After a square container with 4 decimeters of edge length is filled with water, pour the water into a cuboid container with 8 decimeters of length and 4 decimeters of width. What is the depth of the container?


4 × 4 × 4 (8 × 4) = 64 △ 32 = 2 (decimeter) a: the water depth of this container is 2 decimeters



Given the function f (x) = x (x-1) (X-2) (x-3) (x-4). (X-100), find f '(0)=


f'(x)=x'*(x-1)(x-2)(x-3)(x-4).(x-100)+x(x-1)'*(x-2)(x-3)(x-4).(x-100)+…… +x(x-1)(x-2)(x-3)(x-4).(x-100)'=(x-1)(x-2)(x-3)(x-4).(x-100)+x(x-2)(x-3)(x-4).(x-100)+…… +X (x-1) (X-2) (x-3) (x-4). (x-99)



x: How to solve 15 = (x + 10): 18?


Multiply both sides of the equation by 15 * 18 to get:
18x=15(x+10)
3x=15*10=150
x=50



The value of tan10 ° + tan50 ° + 3tan10 ° tan50 ° is ()
A. -3B. 3C. 3D. 33


Tan 10 ° + Tan 50 ° + 3 Tan 10 ° Tan 50 ° = Tan (10 ° + 50 °) (1-tan 10 ° Tan 50 °) + 3 Tan 10 ° Tan 50 ° = 3 (1-tan 10 ° Tan 50 °) + 3 Tan 10 ° Tan 50 ° = 3-3 Tan 10 ° Tan 50 ° + 3 Tan 10 ° Tan 50 ° = 3



A train moves in a straight line at the initial speed of two meters per second and the acceleration of one meter per second to find the final speed of the train in the third second?


First of all, you have to figure out what is acceleration. The velocity unit M / s represents the moving distance per unit time, and the formula v = s / T. acceleration represents the change of velocity per unit time (uniform acceleration is + and uniform deceleration is -), that is, a = △ V / t = (vten-vten) / T → vten = at + vten = - 1 * 3 + 2 = - 1m / s. velocity is negative, indicating that the direction is opposite to the original direction



A unit organizes a basketball league match, one for every two teams, and plans 15 matches. If x teams are invited to participate, the equation can be listed as follows


x(x-1)/2=15
That is, C (x, 2) = 15



How to calculate √ (1 + x) DX,
∫ √ (1 + x ^ 2) DX squared


∫ √(1+x)dx
=∫ (1+x)^1/2dx
=2/3(1+x)^3/2



If 3x > 2Y, Y / x > 1 can be obtained by cross multiplication


No way
First of all, it's not the same thing where cross multiplication comes from;
Secondly, inequality can't be multiplied and divided randomly. If x > 0, the direction of inequality sign doesn't change, but X