If a passenger ship finds a cargo ship 60 ° south by East, the passenger ship will be on the right side of the cargo ship______ Direction

If a passenger ship finds a cargo ship 60 ° south by East, the passenger ship will be on the right side of the cargo ship______ Direction


northwest
Specifically, 60 ° north by West



If the value of the algebraic formula (2x ^ 2 + ax-y + 6) - (- 2bx ^ 2-3x + 5y-1) has nothing to do with the value of the letter X, find the algebraic formula 1 / 3A ^ 3-2b ^ 2 - (1 / 4A ^ 3-3b ^ 2)


(2x ^ 2 + ax-y + 6) - (- 2bx ^ 2-3x + 5y-1) = (2 + 2b) x ^ 2 + (a + 3) x-6y + 7 because it has nothing to do with the value of the letter X, then (2 + 2b) = 0, (a + 3) = 0, then B = - 1, a = - 31 / 3A ^ 3-2b ^ 2 - (1 / 4A ^ 3-3b ^ 2) = 1 / 3A ^ 3-2b ^ 2-1 / 4A ^ 3 + 3B ^ 2 = 1 / 12a ^ 3 + B ^ 2 when B = - 1, a = - 3, the original formula = - 9 / 4 + 1 = - 5 / 4



Two math problems in the first half of the first semester of junior high school!
1. Absolute value of a in a + absolute value of B in B + absolute value of C in C = - 1, find the absolute value of AB in AB + absolute value of BC in BC + absolute value of ABC in ABC
2.2x^5,3x^9,4x^13,5x^17……
1) Please write the 2008 monomial
2) Please write the nth monomial
3) If you subtract the preceding one from the following one, you will get a set of polynomials. Please write the first four polynomials and the nth polynomial, and then answer the degree of the polynomial
Thank you in advance! Get involved quickly One by one, that's fast!
That's the absolute value of the denominator


1. Because the absolute value of a in a + B in B + C in C = - 1. So one number of a, B and C is positive and two are negative. When a is positive, the absolute value of AB in AB + BC in BC + ABC in ABC is - 1 + 1 + 1 = 1



As shown in the figure, the area of parallelogram ABCD is known as ∠ ADO = 90 OA = 5 ob = 3, then ad = 4 AC = 10=


ABCD is a parallelogram, OD = ob = 3, ADO = 90 ° and OA = 5,
∴AD=√(OA^2-OD^2)=4,[AC=2OA=10,BD=2OD=6]
∴SΔADB=1/2AD*BD=12,
S parallelogram ABCD = 24



3,4, - 6,10, 24 o'clock
You know 24 o'clock
Add, subtract, multiply and divide
3 4 -6 10
Make it 24. Each number can only be used once. You can use parentheses and brackets. (at least)
It's not minus 6. That's minus 6


1、4-(-6÷3)×10=24
2、3×(10+(-6)+4)=24
3、10-(-6)×3-4=24



The speed of B is 7 / 8 of that of A. the distance between the two places (as long as the result) can be calculated when they meet 12 kilometers away from the destination


26



The two sides of the isosceles triangle are 2cm and 5cm respectively in the second semester of junior high school?


5+5+2=12
2+2+5=9
But I think 2 + 2 < 5, so it doesn't exist



In isosceles △ ABC, ab = AC, ∠ B = 22.5 °, ab = 2A, calculate the area and perimeter of △ ABC


Let's make CD perpendicular to AB and D through C, and cross the extension line of BA at D. note that D is outside the triangle ∠ BAC = 180 - ∠ B - ∠ C = 180-22.5-22.5 = 135 degrees, so ∠ CAD = 180 - ∠ BAC = 45 degrees. In right triangle CAD, AC = 2A Pythagorean theorem calculates CD = ad = √ 2As = 1 / 2 × ab × CD = 1 / 2 × 2A × √ 2A = √ 2A & # 178; BD = Ba + ad =



What is the formula for tree planting?
......................................................................................................................................................................................................


Basic concepts: planting trees on a line (both ends), then: interval number = the number of trees planted - 1, the number of trees planted = the number of intervals + 1. Improving concepts: 1. The problem of planting trees on a line can be divided into the following three cases. 1. If trees are planted on both ends of the tree planting line, then the number of trees planted should be 1 more than the number of intervals, that is



If the side length of a square is increased by 3cm, its area will be increased by 39cm


Side length = (39-3 × 3) △ 3 △ 2 = 5cm