between on in at in front of next to under behind after like 1.Let’s meet_____ the bus station. 3.We can study the subject______ TV. 4.Please look_____ my son when I'm not at home. 5.There is a dresser____ the wall. 8.Tom looks_____ his father. 10.There is a river____ the house. (fill in the blanks with the words above) Fill in the blanks with between on at in front of next to under behind after like | Math enthusiast | Mathematical art

between on in at in front of next to under behind after like 1.Let’s meet_ the bus station. 3.We can study the subject TV. 4.Please look_ my son when I'm not at home. 5.There is a dresser the wall. 8.Tom looks_ his father. 10.There is a river__ the house. (fill in the blanks with the words above) Fill in the blanks with between on at in front of next to under behind after like

1.at
2. On TV
3. After look after
4on the wall
5 like look like
6in front of
To do this kind of topic, it's better to use the method of exclusion, and accumulate phrases
This one upstairs seems to have made a lot of mistakes_ ∩)o...
Work hard!

In the square castle, 16 guards stood guard along the wall. The team leader assigned them to five on each side, as shown in Figure 9-18. At this time, the squadron leader came. He was not satisfied with the way of distribution, so he ordered to change each side to six. After the squadron leader left, the general came. He thought the squadron leader's order was very inappropriate and lost his temper. Then he changed each side to seven, So what are the two distribution methods?

It turned out that there was a soldier in every corner, except for four corners, three soldiers on each side were not in the corner,
Squadron leader's method: assign 2 soldiers to each corner, 2 soldiers on each side are not in the corner
General's method: three soldiers are assigned to each corner, and one soldier on each side is not in the corner

In triangle ABC, a / cos (A / 2) = B / cos (B / 2) = C / cos (C / 2), then the shape of triangle ABC is?

Equilateral triangle

The image of parabola y = x ^ 2 + BX + C is shifted 3 units to the right, and then 2 units to the down. The expression is y = x ^ 2-3x + 5, and the values of B and C are obtained

The expression: y = x ^ 2-3x + 5 = (x-1.5) ^ 2 + 2.75
Move back = (x-4.5) ^ 2 + 0.75
y=x^2-9x+21
b=-9,c=21

How many tons is one cubic meter

If it's water, 1 cubic meter = 1 ton

Is m / N a monomial or a polynomial

It is neither a monomial nor a polynomial
It's not an integral, it's a fraction

What is the geometric meaning of curve integral

It is these abstract concepts in physics. The first kind is to calculate the density by the shape of the rope with the known linear density. The second kind is to calculate the work with the known variable force and direction of work. So it is also called the curve integral of coordinates. In fact, it is the so-called orthogonal decomposition. If the curve is closed and there is a partial derivative, the plane curve can be transformed into a double integral

Physical unit conversion
The following transformations are ()
A.0.5cm=0.510^-2=510^-3m
B.0.5cm=0.510^-2m=510^-3m
C.0.5cm=0.5cm10^-2=510^-3m
D.0.5cm=0.5cm10^-2m=510^-3m

Choose B, a wrong in the second no unit, D unit repeat, C corresponding proportion error 0.5cm * 10 ^ - 2 = 0.005cm

The law of commutation of addition, the law of combination of addition, the law of commutation of multiplication, the law of distribution of multiplication
Come on, thank you!
Want a letter formula

Additive commutative law: a + B = B + A
Law of combination of addition: (a + b) + C = a + (B + C)
Commutative law of multiplication: a * b = b * a
Multiplicative Association Law: a * b * C = a * (b * c)
Multiplicative distribution law: (a + b) * C = a * C + b * C

A straight line passing through the focus of the parabola y ^ 2 = 2px (P > 0) intersects with the parabola at two points, and the ordinates of the two intersections are Y1 and Y2 respectively; verification: Y1. Y2 = - P ^ 2
Let the equation of the line AB be y = K (X-P / 2), and substitute it into y ^ 2 = 2px
k^2x^2-(2p+k^2p)x+(p^2k^2)/4=0
Let a (x1, Y1), B (X2, Y2), then by WIDA's theorem: x1x2 = [(P ^ 2 k ^ 2) / 4] / (k ^ 2) = (P ^ 2) / 4
The product of the distances from the two intersections to the x-axis is | x1x2 | = (P ^ 2) / 4, which is a constant
Why can't y = kx-p / 2 be a straight line y = K (X-P / 2)
..

K is the slope of a straight line passing through a point. If y-m = K (x-n), there must be a bracket