Given that the solution of equation 3 (5x-6) = 3-20x is also the solution of equation 3a-10x = 6A + 30x, find the value of A

Given that the solution of equation 3 (5x-6) = 3-20x is also the solution of equation 3a-10x = 6A + 30x, find the value of A

Remove the brackets to get 3 (5x-6) = 3-20x, 15x-18 = 3-20x, 15x + 20x = 3 + 18, 35x = 21, x = 35. Substitute x = 35 into the equation 3a-10x = 6A + 30x to get 3a-10 × 35 = 6A + 30 × 35, 3a-6 = 6A + 18, and get a = - 8

The solution of the equation 5x + 10x + A / 4-15x-2a / 4 = 2-5x-3a / 6 is not greater than 4

The first step: merge the similar items 5x = 2-A / 4
The second step: x = 2 / 5 - A / 4 less than or equal to 4
Step 3: A is greater than or equal to - 72

If the equation kx-10x + 3 = 0-solution x = 3 / 4, then K=

Put x = 3 / 4 in
9k/16-10*3/4+3=0
9k/16=9/2
k=8