Both {x = - 2, y = 3 and {x = 2, y = - 1 are the solutions of the equation AX + by = 8

Both {x = - 2, y = 3 and {x = 2, y = - 1 are the solutions of the equation AX + by = 8

-2a＋3b＝8
2a-b＝8,
Add two formulas - 2A + 3B + 2a-b = 8 + 8
b=8,a=4

It is known that x = - 1 is a root of the square - ax + 6 = 0 of the equation X. find a and the other root
Come on!

Substituting x = - 1 into the square of X - ax + 6 = 0:
1+a+6=0
a=-7
x^2+7x+6=0
(x+1)(x+6)=0
The other root is - 6

It is known that one root of the equation x * x-6x + p * p-2p + 5 = 0 about X is 2. Find another root of the equation and the value of P

According to the relationship between the root of the equation and the coefficient, we can get
Sum of two = 6
So the other root is 6-2 = 4
Substituting x = 2 into the equation, we get: 4-12 + p * p-2p + 5 = 0
The result is: P * p-2p-3 = 0
(p+1)(p-3)=0
The solution is p = - 1 or 3