Use a suitable method to solve the following equation: (x + 4) square = 5 (x + 4) And (2) (x + 1) square = 4x (3) (x + 3) square = (1-2x) square (4) 2x square - 10x = 3

Use a suitable method to solve the following equation: (x + 4) square = 5 (x + 4) And (2) (x + 1) square = 4x (3) (x + 3) square = (1-2x) square (4) 2x square - 10x = 3

The first problem, when x = 4 or x = 1, has the solution ~ (2) (x + 1) &# 178; = 4xx & # 178; + 2x + 1-4x = 0x & # 178; - 2x + 1 = 0 (x-1) &# 178; = 0, the solution is: X = 1 (3) (x + 3) &# 178; = (1-2x) &# 178; at the same time, remove the square x + 3 = 1-2x, the solution is x = - 2 / 3 (4) 2 x & # 178; - 10x = 3, both sides divide by 2x simultaneously