The number of solutions of equation (x2 + 3) (x2-2) = 0 is () A. 1B. 2C. 3D. 4

The number of solutions of equation (x2 + 3) (x2-2) = 0 is () A. 1B. 2C. 3D. 4

When equation (x2 + 3) (x2-2) = 0x2 + 3 = 0 or x2-2 = 0x2 + 3 = 0, the equation has no solution; when x2-2 = 0, x = ± 2. The solution of the original equation is x = ± 2, which has two solutions

It is known that the equation 2x square - mx-4 = 0
Let the two original equations be x1, X2, and x1-x2 = 2 √ 3, and find the value of real number M

According to Weida's theorem
x1+x2=m/2,x1x2=-4/2=-2
Because x1-x2 = 2 √ 3
So (x1-x2) ^ 2 = (x1 + x2) ^ 2-4x1x2 = m ^ 2 / 4 + 8 = 12
m^2=16
M = 4 or M = - 4

It is known that the equation MX square (m-1) X-1 = 2x square + X
(1) When m takes what value, the equation is a quadratic equation with one variable. What are the coefficients of the quadratic term, the coefficients of the first term and the constant term?
(2) When m takes what value, the equation is one variable linear equation?

Square of MX + (m-1) X-1 = square of 2x + X
(m-2)x^2+(m-2)x-1=0
(1) When m ≠ 2, the equation is quadratic
Quadratic coefficient m-2
Coefficient of first order term m-2
Constant term - 1
(2) This equation is a linear equation of one variable
m-2=0
m-2≠0
Contradiction!
So there is no M
[welcome to ask, thank you for adopting!]

Two times the square of x minus MX equals 15m square (for the equation of X, 2x ^ 2-mx = 15m ^ 2), find the solution of X

2x² - mx = 15m²
2x² - mx - 15m² = 0
(2x + 5m)(x - 3m) = 0
X = 3m or x = - 5m / 2

Use the formula method to solve the following equation (1 / 3) * x squared - x-0.5 = 0

(1 / 3) x & # 178; - x-0.5 = 0, both sides of the equation multiply by 3 at the same time
x²-3x-1.5=0
a=1 ,b=-3 ,c=-1.5
△=b²-4ac
=(-3)²-4×1×(-1.5)
=9+6
=15
√△=√15
x=(-b±√△)/2a
=(3±√15)/2
x1=(3+√15)/2
x2=(3-√15)/2

The square of X + 2x = 0 solve the equation by formula
Urgent need

x^2+2x=0
a=1 b=2 c=0
X = [- 2 ± root (4-0)] / 2
x=(-2±2）/2 x1=0 x2=-2

The solution of the equation 2x + 5m-6 = 0 of X is x = m2, then the value of 4m2 + 10m is______ ．

Substituting x = M2 into the equation, we can get: 2M2 + 5m-6 = 0, then 2M2 + 5m = 6, х 4m2 + 10m = 2 (2M2 + 5m) = 2 × 6 = 12

On the square of the equation x - (square of M + 3) x + 1 / 2 (square of M + 2) = 0?

x^2-(m^2+3)x+(m^2+2)/2=0
The discriminant is: m ^ 4 + 6m ^ 2 + 9-2m ^ 2-4 = m ^ 4 + 4m ^ 2 + 5=
(m ^ 2 + 2) ^ 2 + 1 > 0, so the equation has two real roots
X1 * x2 = (m ^ 2 + 2) / 2 > 0, so the two roots have the same sign, and because
X1 + x2 = (m ^ 2 + 3) / 2 > 0, so both roots are positive

It is known that the equation x2 + X + n = 0 about X has two real roots - 2, M. find the value of M, n

∵ the equation x2 + X + n = 0 of X has two real roots - 2, m, ∵ 2m = n − 2 + M = − 1. The solution is m = 1n = − 2, that is, the values of M and N are 1 and - 2 respectively

Speed solution of this equation! 20 ﹣ x + 60 ﹣ 2x = 20

Multiply left and right by X
20+30=20x
x=5/2
thank you very much!