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When the distance between two identical metal spheres is r, the interaction force is f Now, if the spheres are separated after contact so that the distance between them is R / 2 and the interaction is 4f / 3, then Q1: Q2 is?
Coulomb force F = kq1.q2/r ^ 2 at the beginning
After contact, they were separated by 4 / 3 F = k [(q1-q2) / 2] ^ 2 / (R / 2) ^ 2
The ratio of the two is 3 / 4 = Q1. Q2 / (q1-q2) ^ 2
We get Q1: Q2 = 1:3 or Q1: Q2 = 3:1
There are two fixed punctual charges in vacuum, the charge quantity is q1.q2, and Q1 > Q2,
When the point charge q is placed at a certain point on Q1. Q1 line, the resultant force of electrostatic force is exactly zero, then ()
A. Q must be a positive charge, B. Q must be a negative charge
C. Q is far away from Q1 and d.q is far away from Q2
Why is the point charge close to the end with less charge?
In order to make sure that the forces are equal in magnitude and opposite in direction, let's look at the formula of Coulomb force
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