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There is a point charge with q = - 3 * 10 ^ - 6C, which moves from point a to point B in an electric field, and the charge does 6 * 10 ^ - 4J work against the electric field force, Move from point B to point C, the electric field force does 9 * 10 ^ - 4J work on the charge, and calculate the potential difference between AB and ac. if B is the zero potential point, the potential at point a is, and the potential at point C is, EPA =, EPC= Please give a detailed explanation
The charge overcomes the electric field force to do work 6 * 10 ^ - 4J, that is, the electric field force does negative work, doing work - 6 * 10 ^ - 4J. According to the definition of potential difference, UAB = φ a - φ B = Δ EP / Q = 200V. If the definition of point B is 0 potential, then the potential of point a is 200V, EPA = - 6 * 10 ^ - 4J. A to C, the total work of electric field force is 3 * 10 ^ - 4J, then UAC = - 100V. The potential of point C is 300V, EPC = - 9 * 10 ^ - 4J
If the positive point charge with charge q = 1.0 × 10-8c is moved from infinity to a point in the electric field, the work to be done by overcoming the electric field force w = 1.2 × 10-4j. Try to find: (1) the electric potential energy of Q at a point and the electric potential at a point (take the electric potential at infinity as zero). (2) what is the electric potential of a point before Q moves into the electric field?
(1) According to the problem, if the positive charge 1.0 × 10-8c moves from infinity to point a in the electric field, the work done by overcoming the electric field force w = 1.2 × 10-4j, and its electric potential energy increases by 1.2 × 10-4j, while the electric potential energy of the positive charge at infinity is zero, then the electric potential energy of Q at point a is EP = w = 1.2 × 10-4j, φ a = EP & nbsp; q = 1.2 × 10 − 41.0 × 10 ·
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