![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
There are two point charges a and B in vacuum, and their charge quantity QA = 2qb. When the distance between them is 0.01cm, the interaction force is 1.8x10 to the - 5th power
It is known that: QA = 2qb, r = 0.01cm = 10 ^ - 4m, f = 1.8x10 ^ - 5, n k = k = 9.0 × 10 ^ 9N & ｛ 8226; M & ｛ 178 / / C & ｛ 178; let: QB = q, then QA = 2q from the expression of Coulomb's Law: F = kq1q2 / R & ｛ 178; get: F = kqaqb / R & ｛ 178
How to calculate the electric field strength at the midpoint of the line when two equal heterogeneous charges (q = 10-8 power C) are separated by a certain distance in vacuum?
Thank you
LS is about the same kind of charge. This problem is about different kinds of charges. They are equal in size and in the same direction
Let the distance be d
Then the E1 generated by the positive charge is KQ / (square of D / 2), and the direction points to the negative charge
The E2 produced by negative charge is the same as that produced by positive charge, but it points to itself
Add it up, e = 2E1 = 2kq / (square of D / 2)
In vacuum, the charge Q1 of negative 9th power C with charge quantity of 2.7 * 10 is attracted by another point charge Q2, which is - 5th power n with charge quantity of 8.0 * 10
The distance between Q1 and Q2 is 0.1M, and the charge quantity of Q2 is calculated
For the point charge in vacuum, use Coulomb's law f = k * Q1 * Q2 / R ^ 2, Q2 = FR / (kq1), K is 9.0 * 10 ^ 9, bring in the data to find the answer
In vacuum, the point a 10 cm away from the point charge Q has a point charge Q of 5.0 × 10, which is negative to the ninth power C and is affected by 3
In vacuum, there is a point charge Q with 5.0 × 10 negative 9th power C at a distance of 10 cm from the point charge Q, which is subjected to the electric field force of 3.0 × 10 negative 4th power n. the electric field strength of point a and the electric quantity of charge q are calculated
Field strength:
E=F/q=(3*10^-4)/(5*10^-9)=(6*10^4)N/C
Power consumption:
E=KQ/r²
Q=Er²/K=(6*10^4)*0.1²/(9*10^9)=6.7*^(-8)C
RELATED INFORMATIONS
- 1. When the distance between two identical metal spheres is r, the interaction force is f Now, if the spheres are separated after contact so that the distance between them is R / 2 and the interaction is 4f / 3, then Q1: Q2 is?
- 2. In vacuum, there are two identical metal spheres (both can be regarded as point charges) with charge quantity - Q1 and + Q2 (Q1 > Q2). When the distance between them is r, the Coulomb force between them is F. now put the two spheres back in contact, and the Coulomb force between them becomes f / 3, what is Q1: Q2
- 3. There is a point charge with charge q = - 3 × 10-6c. When it moves from point a to point B in the electric field, it does 6 × 10-4j work against the electric field force. When it moves from point B to point C, it does 9 × 10-4j work. Question: (1) what are the potential differences among AB, BC and Ca? (2) If the potential at point B is zero, what are the potentials at points a and C? What is the potential energy of charge at a and C?
- 4. The distance between two static point charges in vacuum is 10 cm. The electrostatic attraction between them is 9 times 10 to the negative fourth power. When they join together, they will become a point charge with a charge of 3 times 10 to the negative eighth power Coulomb. How much is the charge of the two points?
- 5. In vacuum, there are two point charges which are 0.3m apart and have the same charge quantity. The electrostatic quantity between them is 1 × 10 to the negative third power In vacuum, there are two point charges which are 0.3m apart and have the same charge quantity. The electrostatic quantity between them is 1 × 10 to the negative third power. How many element charges does each point charge carry?
- 6. There are two point charges in vacuum, Q1 = + 4.0 times 10 to the power of - 8C and Q2 = - 1.0 times 10 to the power of - 8C, which are fixed at x = 0 and x = 6cm respectively Why is the electric intensity always along the positive direction of x-axis between 0-6cm?
- 7. The distance between the moon and the earth is about 3.8 × 15 km. So the distance of the moon around the earth in half a lunar month is________ The magnitude of displacement is_____ km. How to do ah... Understand please make a complete analysis I will be very grateful to you
- 8. It takes 2.56s for the radio wave to return to the earth after it reaches the moon. It is known that the radio wave travels 3 * 10 quintic km per second, and the distance between the earth and the moon is calculated. (the result is accurate to 10000 bits)
- 9. The distance between the moon and the earth is about 390000 km. The information of the moon obtained by the satellite is transmitted back to the earth in the form of radio waves. The propagation speed of radio waves is 3 × 10 ∧ 5. How many seconds does it take for the satellite to transmit the information to the earth
- 10. Merge congeners 2 (a-b) & # 178; - 7 (a-b) & # 179; + 3 (B-A) & # 178; - (B-A) & # 179;
- 11. There is a point charge with q = - 3 * 10 ^ - 6C, which moves from point a to point B in an electric field, and the charge does 6 * 10 ^ - 4J work against the electric field force, Move from point B to point C, the electric field force does 9 * 10 ^ - 4J work on the charge, and calculate the potential difference between AB and ac. if B is the zero potential point, the potential at point a is, and the potential at point C is, EPA =, EPC= Please give a detailed explanation
- 12. Put the test charge of the negative ninth power of Q1 = - 1 × 10 into the electric field P generated by the point charge Q, and the electric field force of Q1 is measured to be the negative sixth power of 1 times 10 If Q1 is removed and a point charge Q2 = 2 times 10 to the power of minus 8 is placed at P point, then the electric field force on Q2 is? What is the electric field strength generated by Q at P point? Direction?
- 13. Given that the a power of 10 = radical 2, the B power of 10 = 4 root 8, find the 2B power of 2a-3 molecule of 10
- 14. The total edge length of a cube is 36cm. After forming two identical cuboids, the total surface area of the two cuboids is larger than that of the original cube The total edge length of a cube is 36cm. After forming two identical cuboids, how much more is the total surface area of the two cuboids than that of the original cube?
- 15. There is a rectangle, its length, width and height are three continuous natural numbers, and its volume is 210 cubic meters?
- 16. A cuboid wood block is cut off from both ends and its surface area is reduced by 80 square centimeters. How many cubic centimeters is the volume of the original cuboid? A cuboid block of wood, cut off from both ends of the cuboid for 2 cm, will become a cube, the surface area reduced by 80 square centimeters?
- 17. A cuboid becomes a cube when its height increases by 4 cm, and its surface area increases by 80 square cm. What is the cuboid's volume in cubic cm? There should be formulas
- 18. It is known that the area of rectangle A and square B is equal, if the length of rectangle A is 4.5x10 to the third millimeter and the width is 32x10 to the second millimeter How many square millimeters is the area of square B
- 19. A rectangular iron plate, 30 cm in length and 25 cm in width. As shown in the figure, cut the square with a side length of 5 cm from four corners, and then make a box. How many ml is the volume of this box?
- 20. Two wires of the same length, one is a cuboid frame of 8 cm long, 5 cm wide and 5 cm high, and the other is a cube frame What is the edge length of this cube frame?