Two wires of the same length, one is a cuboid frame of 8 cm long, 5 cm wide and 5 cm high, and the other is a cube frame What is the edge length of this cube frame?

Two wires of the same length, one is a cuboid frame of 8 cm long, 5 cm wide and 5 cm high, and the other is a cube frame What is the edge length of this cube frame?

(8 + 5 + 5) × 4 △ 12 = 6cm
A: the edge length of this cube frame is 6cm

A wire can be tied into a cuboid frame of 5cm long, 4cm wide and 3cm high

It is made into a cuboid frame of 5cm long, 4cm wide and 3cm high
We need wire
4*(5+4+3)=48cm
Make a cube
Side length
=48/12
=4cm
Surface area
=6*4*4
=96 square centimeters
volume
=4*4*4
=64 CC

A rectangular iron sheet is 30cm long and 25cm wide. Cut off the four corners of the square with 5cm side length to make a uncovered rectangular iron box. What is the volume of the box?

The box is long
30-5 × 2 = 20 (CM)
Box width
25-5 × 2 = 15 (CM)
What's the volume of the box
20 × 15 × 5 = 1500 (CC) = 1.5 (L)

(2012. The three module in Guiping) uses min{a and b} to represent the smallest number in a and B. If function y=min{x2+1, 1-x2}, then Y's image is ().
A. B. C. D.

According to the meaning of the question, min {x2 + 1, 1-x2} denotes the smallest number in x2 + 1 and 1-x2, no matter what value x takes, there is x2 + 1 ≥ 1-x2, so y = 1-x2; it can be seen that when x = 0, y = 1; when y = 0, x = ± 1; then the intersection coordinates of the function image and the X axis are (1,0), (- 1,0); the intersection coordinates with the Y axis are (0,1)

If x is less than 0, what quadrant is the image of function y = - 2x

II

Given that f (x) = SiNx + 3cosx (x ∈ R), the image of the function y = f (x + φ) is symmetric with respect to the line x = 0, then the value of φ can be ()
A. π2B. π3C. π4D. π6

The image of F (x) = SiNx + 3cosx = 2Sin (x + π 3) and function y = f (x + φ) = 2Sin (x + φ + π 3) is symmetric with respect to the line x = 0, the function is even, and φ = π 6, so D

Given the function f (x) = SiNx / 3cosx / 3 + √ 3cos2x / 3, (1) find the coordinate of the symmetry center of the function f (x) image. (2) find the function f if x ∈ (0, π / 3]（
Given the function f (x) = SiNx / 3cosx / 3 + √ 3cos2x / 3,
(1) Find the symmetric center coordinates of the function f (x) image
(2) If x ∈ (0, π / 3], find the range of function f (x)
Given the function f (x) = SiNx / 3cosx / 3 + √ 3 (cosx / 3) ^ 2,
(1) Find the symmetric center coordinates of the function f (x) image
(2) If x ∈ (0, π / 3], find the range of function f (x)

F (x) = (1 / 2) 2sinx / 3cosx / 3 + √ 3coscos2x / 3. = (1 / 2) sin (2x / 3) + √ 3cos2x / 3. = (1 / 4) sin (2x / 3 + π / 3). Let 2x / 3 + π / 3 = k π. X = 3K π / 2 - π / 2. The symmetry center of the function f (x) is: (3K π / 2 - π / 2,0) (K ∈ z) 2. When x = π / 4, sin (2x / 3 + π / 3) = 1

How to draw the image of y = LG (- x + 1)
Why do you draw the image of y = lg|x + 1|first, move it one unit to the left, and then draw the image on the left with x = - 1 as the symmetry axis?
What is the principle of taking x = - 1 as the axis of symmetry?

When x = - 1, x + 1 = 0, and | x + 1 | = y is symmetric with respect to x = - 1, so the image of y = LG | x + 1 | is also symmetric with respect to x = - 1, then drawing one side and the other side is the same

If the image of a function y = 2x + k is known to pass through a point (1,1), then its focus on x-axis is______ The solution of equation 2x + k = 0 is___
ditto.

Substitute (1,1) into y = 2x + K to get
1=2*1+k
k=-1
So y = 2x-1
So the intersection of it and X axis is (1 / 2,0), 2x + k = 0
2x-1=0
The solution is x = 1 / 2

If the image focus of linear function y = - 2x + 4 and y = x + 4 is a (0,4), then the solution of equations 2x + y-4 = 0, X-Y + 4 = 0 is?

Because: as a function of degree, the intersection of images of y = - 2x + 4 and y = x + 4 is at a (0,4)
So: the solution of the equations 2x + y-4 = 0, X-Y + 4 = 0 is x = 0, y = 4