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In vacuum, there are two identical metal spheres (both can be regarded as point charges) with charge quantity - Q1 and + Q2 (Q1 > Q2). When the distance between them is r, the Coulomb force between them is F. now put the two spheres back in contact, and the Coulomb force between them becomes f / 3, what is Q1: Q2
1:3……
Charge sharing after collision, q = (q2-q1) / 2
Then the expressions of Coulomb force are given twice, and the second is one third of the first
You can do it
Under the action of external force, a positive point charge with the charge quantity of + 2x10 to the negative 9th power C moves slowly from point a to point B,
Under the action of external force, a point charge with a charge quantity of + 2x10 to the negative 9th power moves slowly from point a to point B. in this process, the external force does work to the point charge to the negative 6th power of 8 × 10. If the potential of point a is φ A and the potential of point B is φ B, then the following conclusion is correct
A. It can be concluded that φ a - φ B = 4000V
B. It can be concluded that a - B = - 4000V
C (a - b) may be equal to zero
D. It is impossible to judge the value of (a - b)
.
If the work done by electric field force WAB = - 8 * 10 ^ - 6 = q (φ a - φ b), then φ a - φ B = - 4000V
(1 / 3) move the positive point charge of C to the negative eighth power of 2 times 10 from infinity to a point in the electric field, and overcome the electric field force to do work 8 times 10 for the negative sixth time
(1 / 3) move the positive point charge with charge quantity of 2 times 10 to the negative 8th power C from infinite distance to point a in the electric field, overcome the electric field force to do work of 8 times 10 to the negative 6th power coke, and move the charge from infinite to point B in the electric field
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If the point a of 5.0 × 10 negative eighth power charge is moved to the point B in an electric field, the electric field force does the work of 6.0 × 10 negative third power J
If we move a 2.5 × 10 charge of minus 8 power C between a and B, what will the electric field force do
According to the work formula of electric field force on electric charge: (from a to b) WAB = Q * UAB (each quantity contains positive and negative signs), the potential difference of 6 * 10 ^ (- 3) = 5 * 10 ^ (- 8) * uaba and B is UAB = 1.2 * 10 ^ 5V. If the electric charge moves 2.5 × 10 to the negative 8th power C between a and B, the work done by electric field force is wab1 = Q1 * UAB = 2.5 * 10
RELATED INFORMATIONS
- 1. There is a point charge with charge q = - 3 × 10-6c. When it moves from point a to point B in the electric field, it does 6 × 10-4j work against the electric field force. When it moves from point B to point C, it does 9 × 10-4j work. Question: (1) what are the potential differences among AB, BC and Ca? (2) If the potential at point B is zero, what are the potentials at points a and C? What is the potential energy of charge at a and C?
- 2. The distance between two static point charges in vacuum is 10 cm. The electrostatic attraction between them is 9 times 10 to the negative fourth power. When they join together, they will become a point charge with a charge of 3 times 10 to the negative eighth power Coulomb. How much is the charge of the two points?
- 3. In vacuum, there are two point charges which are 0.3m apart and have the same charge quantity. The electrostatic quantity between them is 1 × 10 to the negative third power In vacuum, there are two point charges which are 0.3m apart and have the same charge quantity. The electrostatic quantity between them is 1 × 10 to the negative third power. How many element charges does each point charge carry?
- 4. There are two point charges in vacuum, Q1 = + 4.0 times 10 to the power of - 8C and Q2 = - 1.0 times 10 to the power of - 8C, which are fixed at x = 0 and x = 6cm respectively Why is the electric intensity always along the positive direction of x-axis between 0-6cm?
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- 9. 1. Merge congeners A & # 179; - A & # 178; b-ab & # 178; + A & # 178; B + A & # 178; B + B & # 179; 2. First simplify, and then evaluate 1-4x & # 179; - 5x & # 178; + 2X-4, where x = 2
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- 11. When the distance between two identical metal spheres is r, the interaction force is f Now, if the spheres are separated after contact so that the distance between them is R / 2 and the interaction is 4f / 3, then Q1: Q2 is?
- 12. There are two point charges a and B in vacuum, and their charge quantity QA = 2qb. When the distance between them is 0.01cm, the interaction force is 1.8x10 to the - 5th power
- 13. There is a point charge with q = - 3 * 10 ^ - 6C, which moves from point a to point B in an electric field, and the charge does 6 * 10 ^ - 4J work against the electric field force, Move from point B to point C, the electric field force does 9 * 10 ^ - 4J work on the charge, and calculate the potential difference between AB and ac. if B is the zero potential point, the potential at point a is, and the potential at point C is, EPA =, EPC= Please give a detailed explanation
- 14. Put the test charge of the negative ninth power of Q1 = - 1 × 10 into the electric field P generated by the point charge Q, and the electric field force of Q1 is measured to be the negative sixth power of 1 times 10 If Q1 is removed and a point charge Q2 = 2 times 10 to the power of minus 8 is placed at P point, then the electric field force on Q2 is? What is the electric field strength generated by Q at P point? Direction?
- 15. Given that the a power of 10 = radical 2, the B power of 10 = 4 root 8, find the 2B power of 2a-3 molecule of 10
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