As shown in the figure, ∠ BAC = 105 ° if MP and NQ vertically bisect AB and AC respectively, calculate the degree of ∠ PAQ

As shown in the figure, ∠ BAC = 105 ° if MP and NQ vertically bisect AB and AC respectively, calculate the degree of ∠ PAQ

∵∠ BAC = 105 °, ∵ ABP + ∠ ACQ = 180 ° - 105 ° = 75 °, ∵ MP and NQ divide AB and AC vertically, respectively, ∵ Pb = PA, QC = QA. ∵ PAB = ∵ ABP, ∵ QAC = ∵ ACQ, ∵ PAB + ∵ QAC = ∵ ABP + ∵ ACQ = 75 °, ∵ PAQ = 105 ° - 75 ° = 30 °

In the triangle ABC, the angle BAC is 100 degrees. If MP and NQ divide AB and AC vertically, what is the degree of the angle PAQ?

In the triangle AEC and abd, the two triangles are congruent, and a = 55 degrees, angle AED = angle ADB = 90 degrees, push out angle abd = angle ace = 35 degrees, so angle DBC + angle ECB = 180-55-35 * 2 = 55 degrees, in the triangle BOC, angle BOC = 180-55 = 125 degrees! Too simple~~~~

If in the triangle ABC, the angle BAC = 110 degrees, P and Q are on BC, if MP and NQ bisect AB and AC respectively, then the degree of the angle PAQ is

40 degrees

As shown in the figure, ∠ BAC = 110 ° if MP and NQ vertically bisect AB and AC respectively, then the degree of ∠ PAQ is ()
A. 20°B. 40°C. 50°D. 60°

∵∠ BAC = 110 °, ∵ B + ∠ C = 70 ° and MP, NQ is the vertical bisector of AB and AC, ∵ BAP = ∠ B, ∵ QAC = ∠ C, ∵ BAP + ∠ CAQ = 70 ° and ∵ PAQ = ∠ BAC - ∠ BAP - ∠ CAQ = 110 ° - 70 ° = 40 ° so select: B

As shown in the figure, ∠ BAC = 110 ° if MP and NQ divide AB and AC vertically, then ∠ PAQ=______ ．

∵∠ BAC = 110 °, ∵ B + ∠ C = 180 ° - 110 ° = 70 °, ∵ MP, NQ is the vertical bisector of AB and AC, ∵ AP = BP, AQ = QC (the distance from any point on the vertical bisector of the line segment to the two ends of the line segment is equal),