Add both the numerator and denominator of 113______ It can be divided into 13

Add both the numerator and denominator of 113______ It can be divided into 13

Let X be added to the numerator and denominator of 113 at the same time, which can be reduced to 13. From this, we can get the following equation: & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 1 + x13 + x = 13, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 13 + x = 3 (1 + x), & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 13 + x = 3 + 3x, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 5. & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; so the answer is: 5

If you add a number to the numerator and denominator of 1 / 13 at the same time, it will be divided into 1 / 3. Don't set X

(13-3)÷(3-1)=5

1 in 13, the numerator and denominator plus the same number will be divided into 2 in 3. What is the number added?

(1+x)/(13+x)=2/3
3+3x=26+2x
x=23

48 out of 60 numerator and denominator add the same number at the same time, then 9 out of 13 numerator and denominator add a few

Answer: - 21
Let X be the number added at the same time,
(48+x)/(60+x)=9/13
The solution is: x = - 21