As shown in the picture, the shape of a 40 meter long vegetable greenhouse is a semi cylindrical shape with a 3-meter-high semi-circular brick wall at both ends. The vegetable greenhouse is covered with plastic film until the end How many square meters less plastic film is needed? How many cubic meters of space is the whole vegetable greenhouse?

As shown in the picture, the shape of a 40 meter long vegetable greenhouse is a semi cylindrical shape with a 3-meter-high semi-circular brick wall at both ends. The vegetable greenhouse is covered with plastic film until the end How many square meters less plastic film is needed? How many cubic meters of space is the whole vegetable greenhouse?

It needs 376.8 square meters of plastic film, and the space of the whole vegetable greenhouse is 5086.8 cubic meters

There is a round flower bed in the park, with a circumference of 50.24 meters. There is a 1 meter wide path around it. How many square meters is the area of the path?

Radius of small circle: 50.24 ÷ (2 × 3.14), = 50.24 ÷ 6.28, = 8 (m); radius of big circle: 8 + 1 = 9 (m), area of small road: 3.14 × (92-82), = 3.14 × (81-64), = 3.14 × 17, = 53.38 (M2). Answer: area of small road is 53.38 m2

For a round pool, a 1-meter-wide path should be paved around it. How many square meters is the area of the path?

Radius of inner circle: 4 △ 2 = 2 (m), area of path: 3.14 × (1 + 2) 2-3.14 × 22 = 3.14 × (32-22) = 3.14 × 5 = 15.7 (M2); answer: area of path is 15.7 m2

There is a circular flower bed with a circumference of 50.24 meters in the park. A 2-meter-wide path is built around the flower bed. How many square meters is the area of the path?

2 π r = 50.24, r = 8m
The outer circle area of the road is π R ^ 2 = 3.14 * (2 + 8) ^ 2 = 314
The area of inner circle is π R ^ 2 = 3.14 * 8 ^ 2 = 200.96
The road area is 314-200.96 = 113.04

There is a round flower bed in the park, with a circumference of 50.24 meters. There is a 1 meter wide path around it. How many square meters is the area of the path?

Radius of small circle: 50.24 ÷ (2 × 3.14), = 50.24 ÷ 6.28, = 8 (m); radius of big circle: 8 + 1 = 9 (m), area of small road: 3.14 × (92-82), = 3.14 × (81-64), = 3.14 × 17, = 53.38 (M2). Answer: area of small road is 53.38 m2

The school has a round flower bed with a circumference of 31.4 meters. There is a 1 meter wide path around the flower bed. How many square meters is the area of the path? Add the formula

31.4 ﹣ 3.14 ﹣ 2 = 5m
Radius = 5 + 1 = 6M
The area of the path
=3.14×6×6-3.14×5×5
=34.54 square meters

In order to beautify the campus environment, the school plans to pave a 2m wide circular path around the flower bed (as shown in the picture) with a perimeter of 37.68m. What is the area of the path?

Let R be the radius of the flower bed and R be the radius of the outer circle. According to the formula of the circumference of the circle, there are 2 π r = 37.68r = 6 (m) r = R + 2 = 6 + 2 = 8 (m). The area of this path is s = π (r2-r2) = 3.14 × (82-62) = 87.92 (M2). A: the area of this path is 87.92 m2

Lay a 2-meter-wide lawn around the square flower bed. The total area of the lawn is 40 square meters. How many square meters does the lawn and flower bed cover?

(40-2x2x4) △ 4 △ 2 = 3M
Lawn and flower bed cover an area of (3 + 2 + 2) x (3 + 2 + 2) = 49 square meters

Lay a two meter wide lawn around the square flower bed. The total area of the lawn is 40 square meters. How many square meters does the lawn and flower bed occupy

If the side length of the flower bed is x m, then
(x+2)²-x²=40
4x+4=40
x=9
(9+2)²=121
That is, the lawn and flower bed occupy a total of 121 square meters

It is planned to build a square flower bed and lay a 2 meter wide lawn around the flower bed. The lawn area is 40 square meters
What's the area of the flower bed

40-2 × 2 × 4 = 24 square meters (minus 4 corners (2m × 2m small square)
24 △ 2 = 12m (perimeter of square)
12 △ 4 = 3M (square side length)
3 × 3 = 9 square meters (flower bed area)