7. There are two forces F1 and F2 acting on the same object. When the directions of F1 and F2 are the same, the resultant force is 100N; when the directions of F1 and F2 are opposite, the resultant force is 100N The size is 50N, and the direction is the same as that of F1

7. There are two forces F1 and F2 acting on the same object. When the directions of F1 and F2 are the same, the resultant force is 100N; when the directions of F1 and F2 are opposite, the resultant force is 100N The size is 50N, and the direction is the same as that of F1

F1+F2=100
F1-F2=50
So F1 = 75n
F2=25N

The two forces acting on the same point are F1 = 5N and F2 = 4N. If the angle between the resultant force F and F1 is θ, then θ may be ()
A. 30°B. 45°C. 60°D. 75°

According to the trigonometric rule, two forces F1 and F2, the resultant force F, as shown in the figure, are obtained according to the geometric knowledge. When F2 is perpendicular to the resultant force F, θ is the largest. If the maximum value of θ is θ m, then sin θ M = f2f1 = 45, θ M = 53 °, so θ may be 30 ° and 45 °

An object is in balance under the action of five common forces. Now remove the two forces of F1 = 25N and F2 = 20n, and the remaining three forces remain unchanged. Then the size range of the resultant force of the remaining three forces is____ N
The resultant force of the four forces except F1 is___ N

The resultant force range is 5-45n
The resultant force of the four forces except F1 is 25N

An object is still in the air under the action of the vertical upward force F1, now F1 suddenly increases to F2, the direction does not change, after a period of time, the force F2 does not change, suddenly reverses, and then after the same period of time, the object just arrives at the starting point, and the ratio of F1 to F2 is calculated?

v=[F2-F1]t/m
S=0.5[F2-F1]t2/m
-S=vt-0.5[F2+F1]t2/m
Two formula addition
0.5[F2+F1-F2+F1]t/m=v=[F2-F1]t/m
F1=F2-F1
F2=2F1