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When the horizontal thrust f acts on a, the two objects move together, and the pressure between AB is F1 When the horizontal thrust f acts on a, the two objects move together, and the pressure between AB is F1; when the thrust f acts on B, the two objects move together, and the pressure between AB is F2, then () The acceleration of two motions of a is equal BF1 + F2
A the two forces are the same, the mass is the same, and the acceleration is the same
B. C: F1 = MB * a, F2 = ma * a, so F1 + F2 = (MB + MA) * a = F
D F1：F2=Mb:Ma
(I think M1 = Ma; M2 = MB)
The wood block with mass M1 is placed on a smooth horizontal plane, and the wood block with mass M2 is placed on M1. The horizontal forces F1 and F2 are used successively to make the wood block move to the right without relative sliding. Then what is the ratio of the pulling force used in conjunction?
┏┓m2 m2┏┓→F2
┏m1┓→F1 ┏m1┓
━━━━━━━━━━━━━━━━
If you don't understand the picture, just ignore it,
m2
Solve the following four equations
(m1+m2)a1=F1
m2gμ=m2a1
(m1+m2)a2=F2
m2gμ=m1a2
Solution
m1:m2=F1:F2
RELATED INFORMATIONS
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