1. In triangle ABC, if a = 2, B = root 2, angle a = tt / 4, then angle B is equal to 2. In triangle ABC, if a = root 7, B = 3, C = 2, then angle a is equal to 2 The first and second questions have been solved

1. In triangle ABC, if a = 2, B = root 2, angle a = tt / 4, then angle B is equal to 2. In triangle ABC, if a = root 7, B = 3, C = 2, then angle a is equal to 2 The first and second questions have been solved

First question
a=2,b=√2,∠A=π/4
Sine theorem
a/sinA=b/sinB
2/(√2/2)=√2/sinB
sinB=1/2
∵a>b
∴∠A>∠B
■ ∠ B = 30 ° (omit 150 °)

The distance from the center of a triangle to its vertices is equal______ (fill in "correct" or "wrong")

The outer center of a triangle is the center of the circumscribed circle of the triangle, that is, the intersection of the vertical bisectors of the three sides of the triangle. Its main feature is that the distances to the three vertices of the triangle are equal. Therefore, the original proposition is correct

Proof: in any triangle ABC, the distance from the perpendicular o to the vertex B is twice the distance from the outer center of the triangle ABC to the edge AC

Let G be the outer center of △ ABC, G be the intersection of GD ⊥ AC and D, then take e as the middle point of Ao, and f. ∵ Bo ⊥ AC, Gd ⊥ AC, ∵ GD ⊥ Bo. ∵ AF = BF, AE = OE, ∥ Fe ∥ Bo as the middle point of ab

The distance from the center of a triangle to its vertices is equal______ (fill in "correct" or "wrong")

The outer center of a triangle is the center of the circumscribed circle of the triangle, that is, the intersection of the vertical bisectors of the three sides of the triangle. Its main feature is that the distances to the three vertices of the triangle are equal. Therefore, the original proposition is correct