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If the perimeter of △ ABC is 16cm and the area is 24cm square, the inscribed circle radius of triangle ABC is calculated
The area of triangle is 1 / 2 * r * C, where C is the perimeter and R is the inner and original radius
24=1/2*r*16,r=3
In a right triangle A.B.C, the angle ABC = 90 degree CD is the height of AB side AB = 10cmbc = 8cmac = 6cm (1) find the area of triangle ABC (2) find the length of CD
Angle BCA = 90 (square of 8 + square of 6 = square of 10)
Area of triangle ABC: 8 * 6 / 2 = 24
In triangle ABC and triangle BDC
Angle CDB = angle BCA
CB=BC
Angle B = angle B triangle ABC is similar to triangle BDC
Then: AC / CD = AB / CB, CD = 4.8
If the area of right triangle ABC is 24cm2, the right side AB is 6cm, and ∠ A is an acute angle, then Sina = 0___ ．
According to the Pythagorean theorem, the hypotenuse AC = 10, ﹥ Sina = BCAC = 810 = 45
De is the middle perpendicular of the side ab of the triangle ABC, AC is equal to 5, BC is equal to 8, find the perimeter of the triangle AEC
It's 13
Because De is the vertical line of the edge ab of ABC, ad = BD, ED is perpendicular to AB, then the triangle AED is equal to the triangle EDB, so be = AE, then the perimeter of the triangle AEC = AC + CE + AE = AC + CE + be = AC + BC = 8 + 5 = 13
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