As shown in the figure, in △ ABC, ∠ ABC = 100 °, am = an, CM = CP, then the degree of ∠ NMP is______ ．

∫ ABC = 100 °, ∫ a + B + C = 180 °, ∫ a + C = 180 ° - 100 ° = 80 °, ∫ am = an, CM = CP, ∫ amn = ∫ anm, ∫ CMP = ∫ CPM. According to the inner angle sum theorem of triangle, we can get: ∫ CMP = 12 (180 ° - C) = 90 ° - 12 ‰ C, ∫ amn = 12 (180 ° - a) = 90 ° - 12 ‰ a, ∫

In △ ABC, a = 1, B = 45 ° and s △ ABC = 2, then the diameter of the circumscribed circle of △ ABC is ()
A. 43B. 60C. 52D. 62

∵ a = 1, B = 45 °, s △ ABC = 2, ∵ from the area formula of triangle, s = 12acsin, B = 12 × 1 × C × 22 = 2, ∵ C = 42, a = 1, CoSb = 22. According to the cosine theorem, B2 = 1 + 32-8 = 25, the solution is b = 5. The diameter of circumscribed circle of ∵ ABC is bsinb = 522 = 52, so select C

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As shown in the figure, in △ ABC, ∠ ABC = 100 °, am = an, CM = CP, then the degree of ∠ NMP is______ ．