If a is the inclination angle of the straight line and the tangent Sina + cosa = 1 / 5, then the slope of the straight line L is?

If a is the inclination angle of the straight line and the tangent Sina + cosa = 1 / 5, then the slope of the straight line L is?


Because Sina + cosa = 1 / 5, so Sina = 1 / 5-cosa, and because Sina + cosa = 1, so Sina = - 3 / 5, cosa = 4 / 5, so Tana = - 3 / 4



It is known that the inclination angle of the straight line L is 60 ° and the slope of the straight line is? Thank you!


Given that the inclination angle of the straight line L is 60 °, what is the slope of the straight line?
A: slope k = tan60 ° = √ 3;
The inclination angle θ of a straight line refers to the angle between the upward direction of the straight line and the positive direction of the x-axis; it is specified that 0 °≤ θ



Given that l: 2x-y + 1 = 0, the slope of the line parallel to L is


If the slope of the line L: 2x - y + 1 = 0 is k = 2, then the slope of the line parallel to the line L is 2



The slope k of the straight line passing through two points a (- 2,3) and B (2, - 1)=_______ , inclination angle α=_____


-1, - 45 degrees