It is known that the point oblique equation of line L is Y-2 = X-1, then the slope of line L is -? And the inclination angle is?

y-2=x-1
y=x+1
So the slope is 1 and the tilt angle is π / 2

Given that the slope of the straight line is - 1 and the length of the straight line cut by the circle (x square + y square = 3) is 2, the equation of the straight line is solved

Let the linear equation be y = - x + B

Given that the slope of the line k = 1, and after (1, - 1), what is the equation of the line~

y=kx+b
K = 1, so y = x + B
The line passes through the point (1, - 1), so x = 1, y = - 1 is the solution of the equation. Substituting y = x + B, we can get the following result:
-1 =1+b
b= -2
So the equation of the line is y = X-2

The slope k of the line passing through two points a (1, - 1), B (- 3,2)?

k=(2+1)/(-3-1)=3/(-4)=-3/4

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