If the line L passes through two points a (3,2) and B (1, m ^ 2), the range of inclination angle a of the line L is () The answer is [0,45] u [135180] But I feel that all corners are OK. A = (2-m ^ 2) / 2. Can't all corners be taken

If the line L passes through two points a (3,2) and B (1, m ^ 2), the range of inclination angle a of the line L is () The answer is [0,45] u [135180] But I feel that all corners are OK. A = (2-m ^ 2) / 2. Can't all corners be taken

Let the slope of line l be K. when k ≥ 0, because m ^ 2 ≥ 0, when m ^ 2 = 0, i.e. M = 0, the slope of line L is the largest, then k = (0-2) / (1-3) = 1; when line L is a line, y = 2, the smaller the K is, then k = 0; 0 ≤ k = Tana ≤ 1 ∵ y = Tana (a ≠ (π / 2) + 2K π) is the increasing function in the domain of definition

If the slope of the line L is known to be k = - Tan π / 3, then the inclination angle of the line L is α

2Pi/3

If the slope of the line L is k = - Tan α, (α belongs to π / 2, π), then the inclination angle of the line L is k = - Tan α
A α
B α-π/2
C -α
D π-α

Choose D
Pay attention to the range of tilt angle, exclude C
And the tangent of a, the tangent of B is not in line with the topic

If the inclination angle of a straight line is α, then its slope k = Tan α?

No, when the inclination angle is 90 degrees, the straight line has no slope