Given that the distance difference between the moving point P and the points F1 (- 5,0) and F2 (5,0) is 6, then the trajectory equation of point P is?

The trajectory should be hyperbolic
The distance difference is 6, that is, 2A = 6, a = 3
If C = 5, B = 4
So the trajectory equation of point P is (x ^ 2 / 9) - (y ^ 2 / 16) = 1

Given two fixed points F1 (- 5,0), F2 (5,0), find the trajectory equation of point P whose absolute value of the difference between the distances of F1 and F2 is 8

The trajectory is hyperbolic, F1 (- 5,0), F2 (5,0) is the focus,
c=5,2a=8,a=4,b²=c²-b²=9,
Then the trajectory equation is X & sup2 / 16-y & sup2 / 9 = 1

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