Given the parabola y = x square - (k-1) x-3k-2 and the x-axis image is called two points a (a, 0), B (B, 0), and a square + b square = 17, find K

Given the parabola y = x square - (k-1) x-3k-2 and the x-axis image is called two points a (a, 0), B (B, 0), and a square + b square = 17, find K


The image of parabola y = x square - (k-1) x-3k-2 and X axis is called two points a (a, 0), B (B, 0),
Let a and B be the two roots of the equation x ^ 2 - (k-1) x-3k-2 = 0
Then (k-1) ^ 2 + 4 (3K + 2) > 0, that is k > - 1 or K



Given that the square of parabola y = x - (k-1) x-3k-2 and X axis are at two points a (a, 0) and B (B, 0), and the square of a + the square of B = 17, find the value of K
It's a quadratic function. It's hard,


The original question can be changed into
The solution of the equation x ^ 2 - (k-1) x-3k-2 = 0 (because y = 0 at the intersection) is x = a, x = B
According to Weida's theorem, a + B = - [- (k-1)] / 1 = k-1, a * b = (- 3K-2) / 1 = - 3K-2
a^2+b^2=(a+b)^2-2*a*b=(k-1)^2-2*(-3k-2)
a^2+b^2=17
(k-1)^2-2*(-3k-2)=17
k^2+4k-12=0
k=-6 k=2
If k = - 6, the original formula - (k-1) = - 7 - 3K-2 = 16
[-(k-1)]^2-4*(-3k-2)



Given that the parabola y = xsquare - (k-1) x-3k-2 intersects the X axis at a (a, 0) B (B, 0) and a square + b square = 11, then the value of K is?
Please write down the process


y=x^2-(k-1)x-3k-2
Intersection with X axis at a (a, 0) B (B, 0)
Then a and B are the following two parts of the equation x ^ 2 - (k-1) x-3k-2 = 0
So a + B = k-1
ab=-3k-2
And the discriminant is greater than 0
(k-1)^2-4(-3k-2)>0
k^2+10k+9>0
(k+1)(k+9)>0
k>-1,k-1,k



If the square of parabola y = x - (k-1) x-3k-2 intersects with X at points a (a, 0), B (B, 0) and the square of a + the square of B = 17, then K=______ .
This is the ninth grade on the function point of view to see the quadratic equation of one variable


Δ= (k - 1) ^ 2 + 4 (3K + 2) = k ^ 2 + 10K + 9 > = 0, k = - 1, a + B = k - 1, ab = - 3K-2 from a ^ 2 + B ^ 2 = 17, there is (a + b) ^ 2-2ab = 17 (k-1) ^ 2 + 2 (3K + 2) = 17, k = - 6 (rounding off) or K = 2, so k = 2