As shown in the figure, line a is the U-I diagram line of a power supply, and line B is the U-I diagram line of resistance R. when the power supply and the resistance are used to form a closed circuit, the output power and internal resistance of the power supply are () A. 4W,1ΩB. 6W,1ΩC. 4W,0.5ΩD. 2W,0.5Ω

As shown in the figure, line a is the U-I diagram line of a power supply, and line B is the U-I diagram line of resistance R. when the power supply and the resistance are used to form a closed circuit, the output power and internal resistance of the power supply are () A. 4W,1ΩB. 6W,1ΩC. 4W,0.5ΩD. 2W,0.5Ω


It can be seen from the figure that the electromotive force of the power supply e = 3V, short circuit current I = 6A; then the internal resistance R = EI = 36 Ω = 0.5A; when the resistance is connected with the power supply, the current in the circuit should be 2a, the terminal voltage is 2V, so the output power P = UI = 4W; so select C



The physical meaning of the intersection of power UI line and resistance UI line


It is the voltage and current value corresponding to the maximum power of electrical appliances in actual operation under such power supply



Ohm's law of closed circuit
High school physics elective 3-1 said: when the external circuit is disconnected, r = ∞, I = 0, IR = 0, u = E. but when I = 0, IR should also be = 0, that is, u = 0, so it is impossible to measure the electromotive force. What's the matter? Where R is the external resistance circuit, R is the internal resistance circuit, I is the current of the closed circuit, e is the electromotive force of the power supply_ ∩)o...
What I mean is: there is a formula e = IR + IR, if when I = 0, IR is equal to 0, uine = E. but what is deduced from the book is u = e, what's wrong with me?


Conceptual error
U refers to the external pressure, e is the electromotive force, if there is internal resistance, e = u + u when the circuit is closed
(U is internal resistance voltage)
So u = 0 doesn't mean e = 0