Given that the distance from the moving point P to the fixed point F (3,0) and to the fixed value line x = 5 / 2 is constant 2 √ 3 / 3, the trajectory equation of point P is obtained Urgent``

Given that the distance from the moving point P to the fixed point F (3,0) and to the fixed value line x = 5 / 2 is constant 2 √ 3 / 3, the trajectory equation of point P is obtained Urgent``


Let P (x, y)
√(x-3)^2+y^2=(2√3/3)*|x-5/2|
Two sides square
x^2-6x+9+y^2=(4/3)(x^2-5x+25/4)
3x^2-18x+27+y^2=4x^2-20x+25
(x-1)^2/3-y^2=1



In Cartesian coordinate system, the line y = 2x + 2 intersects the x-axis at point a, and the line y intersects the y-axis at point B. if C is a point in the second quadrant, the distance to the x-axis is 1, the distance to the y-axis is half, and CD is perpendicular to the x-axis at d, then whether there is a point P on the x-axis is a triangle, CDP is all equal to AOB? Explain the reason


A (- 1,0) B (0,2) C (- 1 / 2,1) d (- 1 / 2,0)
Let the coordinates of point p be (x0,0)
AO=1,BO=2,CD=1
If congruent, then: DP = 2
P (- 5 / 2,0) or P (3 / 2,0)



In the space rectangular coordinate system, given the points a (1,0,2), B (1, - 3,1), the point m is on the Y axis, and the distance from m to a and B is equal, then the coordinate of M is ()
A. (0,-1,0)B. (0,1,0)C. (1,0,1)D. (0,1,1)


Let m (0, y, 0) get y = - 1 from 12 + Y2 + 4 = 1 + (y + 3) 2 + 1, so m (0, - 1, 0) is selected: a



In the space rectangular coordinate system, given the points a (1,0,2), B (1, - 3,1), the point m is on the Y axis, and the distance from m to a and B is equal, then the coordinate of M is ()
A. (0,-1,0)B. (0,1,0)C. (1,0,1)D. (0,1,1)


Let m (0, y, 0) get y = - 1 from 12 + Y2 + 4 = 1 + (y + 3) 2 + 1, so m (0, - 1, 0) is selected: a