A ten digit number containing ten digits of 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9 is called a "perfect number". If a "perfect number" satisfies the following requirements: (1) it can be divisible by 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12 respectively; (2) its sum with 2004 can be divisible by 13; then what is the smallest of such "perfect numbers"___ ．

A ten digit number containing ten digits of 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9 is called a "perfect number". If a "perfect number" satisfies the following requirements: (1) it can be divisible by 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12 respectively; (2) its sum with 2004 can be divisible by 13; then what is the smallest of such "perfect numbers"___ ．

1. Because 0 + 1 + 2 + +8 + 9 = 45, so the arrangement of any ten numbers can be divided by 3 and 9; 2. Secondly, the number should be divisible by 2, 5 and 10, so the last digit must be 0; 3. Because this number is required to be the smallest, the small number should be put in the front, the large number should be put in the back as far as possible, assuming that the first four digits are 1234; 4. Because this number can be divided by 8, the penultimate digit should be even, and as large as possible, take 8; similarly, the reciprocal number The third digit is 6; to sum up, this number is 1234 680, the number satisfying this form must be 1, 2, 3, 4, 5, 6, 8 and 9; now fill in the space of 5, 7 and 9 to make it divisible by 7, and the minimum can be. Through the test, 1234759680 can be divisible by 11 and 12. Therefore, the minimum of such "perfect number" is 1234759680. So the answer is: 1234759680